Answer:
4.9h−2.7d−13
Step-by-step explanation:
Answer:
6 swimmers in the first heat can be arranged in 1716 different ways.
Step-by-step explanation:
A swim meet has 13 contestants signed up. To calculate the arrangement of first 6 swimmers in first heat we will use combinations because order doesn't matter.
So to select 6 swimmers out of 13 contestants number of different ways
= ![^{13}C_{6}](https://tex.z-dn.net/?f=%5E%7B13%7DC_%7B6%7D)
= ![\frac{13!}{(6!)(13-6)!}](https://tex.z-dn.net/?f=%5Cfrac%7B13%21%7D%7B%286%21%29%2813-6%29%21%7D)
= ![\frac{13\times 12\times 11\times 10\times 9\times 8\times 7!}{6!\times 7!}](https://tex.z-dn.net/?f=%5Cfrac%7B13%5Ctimes%2012%5Ctimes%2011%5Ctimes%2010%5Ctimes%209%5Ctimes%208%5Ctimes%207%21%7D%7B6%21%5Ctimes%207%21%7D)
= ![\frac{13\times 12\times 11\times 10\times 9\times 8}{6\times 5\times 4\times 3\times 2\times 1}](https://tex.z-dn.net/?f=%5Cfrac%7B13%5Ctimes%2012%5Ctimes%2011%5Ctimes%2010%5Ctimes%209%5Ctimes%208%7D%7B6%5Ctimes%205%5Ctimes%204%5Ctimes%203%5Ctimes%202%5Ctimes%201%7D)
= ![\frac{1235520}{720}](https://tex.z-dn.net/?f=%5Cfrac%7B1235520%7D%7B720%7D)
= 1716
Therefore, 6 swimmers in the first heat can be arranged in 1716 different ways.
Answer:
6 mm
Step-by-step explanation:
Use the Pythagorean Theorem to solve for the unknown leg
![a^{2} +b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
Since we need to solve for a, we will manipulate the equation in terms of b and c → ![a=\sqrt{c^{2}-b^{2} }](https://tex.z-dn.net/?f=a%3D%5Csqrt%7Bc%5E%7B2%7D-b%5E%7B2%7D%20%20%7D)
Here, b = 7 mm and c =
mm
Plugging these numbers into our equation gives us
→
=
= 6 mm
Answer:
Y is also 5 bro that is very easy question
Answer:
663
Step-by-step explanation:
the total number of students can be determined using this equation :
(total ratio of Chinese and Indian students / total ratio of students) x n = 468
total ratio of Chinese and Indian students = 4 + 8 = 12
total ratio of students 4 + 8 + 5 = 17
N = TOTAL NUMBER OF STUDENTS
12/17) x n = 468
multiply both sides of the equation by 17/12
n = 663