NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, in terms of time is given by h=−4.9t2+244t+269.
1 answer:
Answer: The height of the rocket after 9 seconds is 2068.1 meters.
The height of the rocket when it initially launched is 269 meters.
Step-by-step explanation:
Given, NASA launches a rocket at seconds.
Its height, in meters above sea-level, in terms of time is given by
To find, the height of the rocket after 9 seconds put t=9, we get
Hence, the height of the rocket after 9 seconds is 2068.1 meters.
To find, the height of the rocket when it initially launched put t=0, we get
Hence, the height of the rocket when it initially launched is 269 meters.
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Answer:
The vertex of this parabola, , can be found by completing the square.
Step-by-step explanation:
The goal is to express this parabola in its vertex form:
,
where ,
, and
are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at
.
The vertex form can be expanded to obtain:
.
Compare that expression with the given equation of this parabola. The constant term, the coefficient for , and the coefficient for
should all match accordingly. That is:
.
The first equation implies that is equal to
. Hence, replace the "
" in the second equation with
to eliminate
:
.
.
Similarly, replace the "" and the "
" in the third equation with
and
, respectively:
.
.
Therefore, would be equivalent to
. The vertex of this parabola would thus be:
.