Question

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, in terms of time is given by h=−4.9t2+244t+269.

Answer 1

Answer: The height of the rocket after 9 seconds is 2068.1 meters.

The height of the rocket when it initially launched is 269 meters.

Step-by-step explanation:

Given, NASA launches a rocket at $t=0$ seconds.

Its height, in meters above sea-level, in terms of time is given by $h=-4.9t^2+244t+269.$

To find, the height of the rocket after 9 seconds put t=9, we get

$h=-4.9(9)^2+244(9)+269\\\\=-4.9(81)+2196+269\\\\=-396.9+2465\\\\=2068.1$

Hence, the height of the rocket after 9 seconds is 2068.1 meters.

To find, the height of the rocket when it initially launched put t=0, we get

$h=-4.9(0)^2+244(0)+269\\\\=0+0+269\\\\=269$

Hence, the height of the rocket when it initially launched is 269 meters.