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xeze [42]
3 years ago
5

What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​

Mathematics
1 answer:
LenKa [72]3 years ago
5 0

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

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Fudgin [204]

Answer:

1/6

Step-by-step explanation:

Solve-

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12m+12 = 14

Subtract 12 form both sides of the equation:

12m+12= 14

12m+12-12 =14-12

Simplify:

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12m=14-12

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Simplify again:

Cancel out the terms:

12m/12=2/12

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3 years ago
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denpristay [2]

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Flura [38]
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krok68 [10]

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