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s344n2d4d5 [400]
2 years ago
15

What is the value of the expression? -16+12

Mathematics
2 answers:
Gwar [14]2 years ago
6 0

Answer:12-16=-4

Step-by-step explanation:the answer is the same way it’s just flipped

Minchanka [31]2 years ago
5 0
The answer is -16+12 =-4
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Write the equation of a line that goes through point (0, 1) and has a slope of 0.
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Answer:

y=1

Step-by-step explanation:

the "mx" part of the equation is the slope, since we need the slope to be zero, there won't be anything in the "mx" part. The "+b" bart of the equation is the y-intercept, since we need the y-intercept to be one, the "+b" part will be 1.

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3 years ago
Simplify the expression 5+(4+x)
photoshop1234 [79]
5 + 4x
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4 0
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Which 2 values of x are roots of the polynomial below?
Alexxx [7]

Given:

The given polynomial is:

f(x)= 3x^{2}-3x+1

To find the roots of the given polynomial.

To find the roots we have to take f(x) = 0

So,

3x^{2} -3x+1 = 0

Formula

By quadratic formula, the root of the equation ax^{2} +bx+c = 0 is,

x = \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2} -4ac} }{2a}

Now,

Putting, a=3, b=-3, c=1 we get,

x = \frac{3+\sqrt{3^{2}-4(3)(1) } }{(2)(3)} and \frac{3-\sqrt{3^{2}-4(3)(1) } }{(2)(3)}

x = \frac{3+\sqrt{-3} }{6} and x=\frac{3-\sqrt{-3} }{6}

Hence,

The values of the roots of the given polynomial arex=\frac{3+\sqrt{-3} }{6} and x=\frac{3-\sqrt{-3} }{6}

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5 0
3 years ago
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oksian1 [2.3K]
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5 0
4 years ago
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Ber [7]

Answer:

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Plug in 2 every time you see an x within the equation: x = 2

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f(2) = -2 + 7

f(2) = 5

4 0
3 years ago
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