Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant = 
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r = 
M = 
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.
<span>Changes in the forms of energy are called "Energy Conversions"
Hope this helps!</span>
Answer:
23
Explanation:
First, we need to convert the hose diameter from inches to meters.
0.75 in × (2.54 cm / in) × (1 m / 100 cm) = 0.0191 m
Calculate the flow rate given the velocity and hose diameter:
Q = vA
Q = v (¼ π d²)
Q = (0.30 m/s) (¼ π (0.0191 m)²)
Q = 8.55×10⁻⁵ m³/s
Find the volume of the pool:
V = π r² h
V = π (1.5 m)² (1.0 m)
V = 7.07 m³
Find the time:
t = V / Q
t = (7.07 m³) / (8.55×10⁻⁵ m³/s)
t = 82700 s
t = 23 hr
Answer:
255 metres
Explanation:
The answer to thi question is actually quite simple. Since the car goes for 3.4 seconds, and it goes 75 metres every second, the answer is just 3.4 multiplied by 75 Metres.
Hello!
Your answer is .92 g/ml.
The equation for density is as follows: D=m/v (density=mass(in g) ÷ volume (in mL))
All you have to do is plug in your numbers (12g, and 13mL) and there you go!
Hope this helps now and in the future!
Brady
