We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
Answer:
8m/s
Explanation:
Average Speed = distance / time = 400/50 = 8m/s
Answer: 0.86 × 10^14
Explanation:
Given the following :
Radius of proton = 1.2 × 10-15 m
Radius of hydrogen atom = 5.3 × 10-11 m
Density of proton could be calculated thus:
Mass of proton = 1.67 × 10^-27 kg
Using the formula :
(4/3) × pi × r^3
(4/3) × 3.142 × (1.2 × 10^-15)^3 = 7.24 × 10^-45
Density = mass / volume
Density = (1.67 × 10^-27) / ( 7.24 × 10^-45)
= 0.2306 × 10^18
Density of hydrogen atom:
Mass of hydrogen atom= 1.67 × 10^-27 kg
Using the formula :
(4/3) × pi × r^3
(4/3) × 3.142 × (5.3 × 10^-11)^3 = 6.24 × 10^-31
Density = mass / volume
Density = (1.67 × 10^-27) / ( 6.24 × 10^-31)
= 0.2676 × 10^4
Ratio is thus:
Density of proton / density of hydrogen atom
0.2306 × 10^18 / 0.2676 × 10^4 = 0.8617 × 10^14
Answer:
Explanation:
Force between two charges is given by the following expression
F = 
Q₁ and Q₂ are two charges and d is distance between two.
.1 =
If Q₁ becomes three times , force will become 3 times . Hence force becomes .3 N in the first case.
Force F = .3 N
If charge becomes one fourth , force also becomes one fourth .
F= 
= .025 N.
Answer:
V = 6.65 [volt]
Explanation:
We must first find the power generated, power is defined as the amount of energy consumed or generated in a given time.
where:
P = power [w]
E = energy = 40 [J]
t = time = 30 [s]
![P =40/30\\P = 1.33[w]](https://tex.z-dn.net/?f=P%20%3D40%2F30%5C%5CP%20%3D%201.33%5Bw%5D)
Now we can calculate the voltage or potential drop by means of the power, the power is calculated by means of the product of the voltage by the current.
where:
V = voltage [volts]
I = current = 200mA = 0.2 [A]
![V = P/I\\V = 1.33/0.2\\V = 6.65 [Volt]](https://tex.z-dn.net/?f=V%20%3D%20P%2FI%5C%5CV%20%3D%201.33%2F0.2%5C%5CV%20%3D%206.65%20%5BVolt%5D)
