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cupoosta [38]
3 years ago
8

Which formula can be used to find the tangential speed of an orbiting object?

Physics
2 answers:
Naily [24]3 years ago
8 0

Answer:

I think the answer is C. V= G  m central/r

Explanation:

Luden [163]3 years ago
6 0
The correct formula for calculating the tangential speed of an orbiting object is V(t)=wr.
V(t)= Tangential Speed
w= Angular Velocity
r= Radius of the Path

Hope this helps.
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Determine which heat transfers below are due to the process of conduction. I) You walk barefoot on the hot street and it burns y
Rudik [331]

I) You walk barefoot on the hot street and it burns your toes.

The road is in direct contact with your skin. Thermal energy from the road will transfer to the bottom of your feet, then to the rest of your body. This is an example of conduction.


II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.

Just like in the previous example, the hot leather is in direct contact with your skin (I guess if you're going to drive naked). Thermal energy from the leather will transfe to your skin, then to the rest of your body. This is also conduction.


III) A flame heats the air inside a hot air balloon and the balloon rises.

The flame heats air directly at the bottom of the balloon. The warm air expands and becomes less dense. This will rise and let the unheated, denser air in the balloon fall down toward the flame. This is an example of the convection cycle.


IV) A boy sits to the side of a campfire. He is 10 feet away, but still feels warm.

The campfire heats air directly nearby. The warm air expands and moves away from the fire in all directions, leaving behind unheated, denser air to be heated up. Some of the warm air reaches the boy. This is another example of convection.


The answer is A) 1 and 2.

3 0
3 years ago
Read 2 more answers
Complete the equation???
soldi70 [24.7K]

Here in nuclear reaction we can say that sum of neutrons and protons in reactant side and product side will be same always

Here mass number on the product side is given to us

so sum of mass number is given as

A_1 + A_2 = 265 + 1 = 266

now on the reactant side also the number must be same

A_1' + A_2' = 58 + x

now we will have

58 + x = 266

x = 208

Now number of protons on product side is given as

P_1 + P_2 = 108 + 0

now we also know that atomic number of Fe is 26

so now we will have

P_1' + P_2' = 108

26 + P_2' = 108

P_2' = 82

now the equation is given as

_{26}^{58}Fe + _{82}^{208}Pb = _{108}^{266}Hs + _0^1X

8 0
2 years ago
A 1.5m wire carries a 6 A current when a potential difference of 68 V is applied. What is the resistance of the wire?
ANTONII [103]

Answer:

11.3 \Omega

Explanation:

We can find the resistance of the wire by using Ohm's law:

V=RI

where

V is the voltage applied

R is the resistance

I is the current

In this problem, we know I = 6 A and V = 68 V, so we can re-arrange the equation to find the resistance of the wire:

R=\frac{V}{I}=\frac{68 V}{6 A}=11.3 \Omega

6 0
3 years ago
Which of the following prefixes represents the largest value
Zigmanuir [339]
C should be right ok



7 0
3 years ago
A skateboarder jumps horizontally off the top of a staircase and lands at bottom of the stairs. The staircase has a horizontal l
e-lub [12.9K]

Answer:

The vertical velocity of the skater upon landing is 10.788 meters per second.

Explanation:

Skateboarder experiments a parabolic movement. As skateboarder jumps horizontally off the top of the staircase, it means that vertical component of initial velocity is zero and accelerates by gravity, the final vertical speed is calculated by the following expression:

v = v_{o} + g\cdot t

Where:

v_{o} - Initial vertical speed, measured in meters per second.

v - Final vertical speed, measured in meters per second.

g - Gravitational acceleration, measured in meters per square second.

t - Time, measured in seconds.

Given that v_{o} = 0\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}} and t = 1.10\,s, the final velocity of the skater upon landing is:

v = 0\,\frac{m}{s} + \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (1.10\,s)

v = -10.788\,\frac{m}{s}

The vertical velocity of the skater upon landing is 10.788 meters per second.

3 0
3 years ago
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