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Rom4ik [11]
2 years ago
13

C) Write the equation in factored form. The equation is y= x^2 - 8x - 20 // Need answer ASAP

Mathematics
1 answer:
netineya [11]2 years ago
8 0

The first term will be an x because

x squared breaks down as x times x.

First look for factors of your constant that add to your

coefficient of the middle term in the trinomial.

Also note that the constant is negative and a negative

factors as the product of a positive and a negative.

The factors of -20 that add to -8 are -10 and +2.

So we have y = (x - 10)(x + 2).

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If it’s out of 180 degrees it’s 30 degrees
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Dave and 6 friends went to dinner. They split the bill evenly. The total for the meal was $84. How much did each friend pay
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Step-by-step explanation:

Dave + 6 friends = 7 friends in total

84 ÷ 7 = 12

Each friend paid $12

4 0
2 years ago
Round 1,819 to the nearest 100
Naddika [18.5K]

Answer:

1,800

Step-by-step explanation:

1,819

----^

1 is less than five so you round down even if you round the 19 to 20 it would still be needed to round down because it is less than 50.

Hope this helps, have a good day! :)

(Brainliest would be appreciated?)

6 0
3 years ago
2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.
likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4  + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

y = ^+_- \sqrt{-x^2+4x+4} -5

Thus

f(x) = \sqrt{-x^2+4x+4} - 5

g(x) = -\sqrt{-x^2+4x+4} - 5

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0

The quadratic has roots

\frac{52 ^+_-\sqrt{1664}}{26}

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0
2 years ago
a 10 gram sample of a substance that's used to detect explosives has k-value of 0.1353, find the substance half life in days, Ro
IrinaK [193]
We find the value of N₀ since we are provided with initial conditions.
The condition is that, at time t = 0, the amount of substance contains originally 10 grams.
We substitute:
10 = N₀ (e^(-0.1356)*0)
10 = N₀ (e^0)
N₀ = 10

When the substance is in half-life (meaning, the half of the original amount), it contains 5 grams. We solve t in this case.
5 = 10 e^(-0.1356*t)
0.5 = e^(-0.1356*t)
Multiply natural logarithms on both sides to bring down t.
ln(0.5) = -0.1356*t
Hence,
t = -(ln(0.5))/0.1356
t ≈ 5.11 days (ANSWER)
4 0
3 years ago
Read 2 more answers
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