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4 years ago

What is 12/30 simplified

Mathematics

1 answer:

brilliants [131]4 years ago

4 0

2/5
.............................

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The product of all natural numbers less than or equal to n is what

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"n factorial" is the product of such numbers.

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Alison bought 12 shares in The Toy Company when it cost $27. She is planning on selling her shares and they currently cost $39.5

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I think the answer I s D

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What is the sum of ¾ + ⅔ in simplistic form

fiasKO [112]

We must find the common denominator.

The list of multiples of 4: 0, 4, 8, 12, 16, 20, ...

The list of multiples of 3: 0, 3, 6, 9, 12, 15, 18, ...

The common denominator is 12.

$\dfrac{3}{4}=\dfrac{3\cdot3}{4\cdot3}=\dfrac{9}{12}\\\\\dfrac{2}{3}=\dfrac{2\cdot4}{3\cdot4}=\dfrac{8}{12}$

Therefore:

$\dfrac{3}{4}+\dfrac{2}{3}=\dfrac{9}{12}+\dfrac{8}{12}=\dfrac{9+8}{12}=\dfrac{17}{12}=\dfrac{12+5}{12}=1\dfrac{5}{12}$

<h3>Answer: 17/12 = 1 5/12</h3>

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4 years ago

A fence is to be built to enclose a rectangular area of 210 square feet. The fence along three sides is to be made of material t

Serhud [2]

Answer with explanation:

Let the length of rectangular fence = x meters

Let the width of the rectangular fence = y meters

Thus

$Area=x\times y=210ft^{2}...........(i)$

Now Let the total cost to construct the fence be 'C' can be obtained if we construct the shorter side with material with cost $12 per foot

$\therefore C=5\times (2y+x)+12\times x\\\\C=10y+17x...............(ii)$

Using value of x from the equation i into equation ii we get

$C=10y+17\times \frac{210}{y}$

hence to minimize the cost we differentiate both sides with respect to 'y' and equate the result to zero thus we get

$C=10y+17\times \frac{210}{y}\\\\\frac{dC}{dy}=\frac{d}{dy}(10y+\frac{3570}{y})\\\\0=10-\frac{3570}{y^{2}}\\\\\therefore y=\sqrt{\frac{3570}{10}}=18.894feet$

Thus $x=\frac{210}{18.894}=11.11feet$

Thus value of length = 11.114 feet and value of width = 18.894 feet.

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If 45 cattle are 30% of the herd, what is the total size of the herd?

Olegator [25]

150 cattle is the answer.

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