All categories

3 years ago

I need help with these two problems... PLZ HELP ME!!!!!!!

Mathematics

1 answer:

hichkok12 [17]3 years ago

3 0

Answer:

3-B,E

4-. ( 1/8)×π×100

arc length of an enclosed circle is 2πr where r is the radius

the atc length of is proportional to the angle subtended at the centre . i.e for this arc it is 1/4th (90°/360°) of the arc length of an enclosed circle.

it is the same relationship with area of a sector

You might be interested in

Eira created color panels for a wall using a mix of only red and blue paints. She plotted the quantities of red and blue paints

lesya [120]

Answer:

3 ≤ x ≤ 7 or x is between 3 and 7, inclusive

Step-by-step explanation:

Eira's graph probably resembled the diagram below.

The domain is the set of all possible x-values that will make a function work.

x can take any value from 3 to 7.

The domain is [3, 7] or 3 ≤ x ≤ 7.

4 0

3 years ago

A quadratic equation is shown:

insens350 [35]

Answer:

<em>The correct answer is the first option</em>

Step-by-step explanation:

<u>Quadratic Equation</u>

The standard form of a quadratic equation is

$ax^2+bx+c=0$

Sometimes we need to change the expression of the same equation to the form

$(x-p)^2=q$

To accomplish that change, we usually modify the left-hand expression to make it look like the square of a binomial.

The given quadratic equation is

$x^2-14x+41=0$

Recall the square of a binomial is

$(x-p)^2=x^2-2px+p^2$

The first term is already present. The second term gives us the value of p:

$-2px=-14x$

Solving

$p=7$

Now we need to produce the third term $p^2=49$ . We only have 41, thus we need to add 8 to both sides of the equation:

$x^2-14x+41+8=0+8$

The correct answer is the first option

7 0

3 years ago

Answer this question correctly, please give the correct answer.

Advocard [28]

X = -2

set equations equal and solve
2x+7 = -x+1
collect like terms
3x = -6
divide
x=-2

7 0

3 years ago

Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is: