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3 years ago

Terrance picked 115.2 pounds of apples on Monday.

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

6 0

Answer:

212.8

Step-by-step explanation:

add the decimals

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Given f-1(x)=-34x+2, which equation represents f(x)?

Elina [12.6K]

There is the answer

4 0

2 years ago

Please help meeeee I don’t really understand it

vredina [299]

3*3+4*4=x*x and 9+16=25 so x is 5 and then add other sides so 5+8+4+5

7 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago

Given the parabola below, find the endpoints of the latus rectum. (x-2)^2=-20(y+2)

Shtirlitz [24]

Answer:

The endpoints of the latus rectum are $(12, -7)$ and $(-8, -7)$ .

Step-by-step explanation:

A parabola with vertex at point $C(x, y) = (h,k)$ and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

$(x-h)^{2} = 4\cdot p \cdot (y-k)$ (1)

Where:

$y$ - Independent variable.

$x$ - Dependent variable.

$p$ - Distance from vertex to the focus.

$h$ , $k$ - Coordinates of the vertex.

The coordinates of the focus are represented by:

$F(x,y) = (h, k+p)$ (2)

The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that $h = 2$ , $k = -2$ and $p = -5$ , then the latus rectum is between the following endpoints: