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kobusy [5.1K]
3 years ago
11

If f(x)=8x+5, what is f(x)^-1?

Mathematics
1 answer:
Molodets [167]3 years ago
7 0
F(8x+5)^-1=0.2

(8+5)^-1=0.077
5^-1=0.2
8x^-1=0.125
0.125-0.2=-0.075/0.2-0.125=0.075
You might be interested in
The cost of 5kg of rice is Rs.425. find the cost of 1kg of rice ​
DaniilM [7]

Answer:

Rs 85

Step-by-step explanation:

Cost of 5kgs of rice = Rs 425

Cost of 1 kg of rice = 425/5

= Rs 85

So, the cost of a kg of rice is Rs 85

8 0
2 years ago
Greek city-states began to form in 800 B.C. and in 200 A.D, Christians began getting persecuted. How many years passed between t
asambeis [7]

Answer: 1000 years

Step-by-step explanation:

-Greek city-states began to form in 800 B.C i.e 800 years Before Christ appearance

- up till 200 A.D i.e 200 years of After Christ disappearance

Hence, the number of years between the time that Greek city-states began to form and the persecution of Christians began is equal to the sum of years Greek city States started formation and Year persecution began

i.e 800 BC + 200 A.D = 1000 Years

Thus, the number of years of that passed was 1000 years

6 0
3 years ago
angle EFG and angle GFH are a linear pair, m angle GFH= 2n+38 and m angle GFH=2n+38. what are m angle EFG and m angle GFH
motikmotik

Answer:

Part 1) m∠EFG=94°

Part 2) m∠GFH=86°

Step-by-step explanation:

we know that

m∠EFG+m∠GFH=180° -----> by linear pair (given problem)

we have

m∠EFG=3n+22

m∠GFH=2n+38

substitute the values

(3n+22)°+(2n+38)°=180°

Solve for n

(5n+60)=180

5n=180-60

5n=120

n=24

<em>Find the measure of angle EFG</em>

m∠EFG=3n+22

substitute the value of n

m∠EFG=3(24)+22=94°

<em>Find the measure of angle GFH</em>

m∠GFH=2n+38

substitute the value of n

m∠GFH=2(24)+38=86°

5 0
3 years ago
Read 2 more answers
angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
4 years ago
Find the domain of the function (ƒ • g)(x) where ƒ(x) = 2x2 + x, g(x) = 5x – 1
asambeis [7]

Not sure if that's a multiplication or a composition. It doesn't matter. Both f and g have a domain of all real numbers. The domain of

( f \circ g)(x)=f(g(x))

is the same as the domain of g(x), all real numbers

Answer: all real numbers


7 0
3 years ago
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