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3 years ago

Can someone explain me to me how to solve this

Mathematics

1 answer:

matrenka [14]3 years ago

4 0

Answer:

4/10 or simplified to 2/5

Step-by-step explanation:

when dividing fractions by a whole number, you want to imagine the whole number as a fraction. which would be 2/1. So you want to use the reciprocal of 2/1 which is 1/2. Then you multiple 4/5 by 1/2 which is 4/10 or simplified to 2/5 hope this helps :)

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Please help !! Geometry homework. Will mark brainliest answer !

sergeinik [125]

For this case we have:

By trigonometric property we have:

$Cosine(\alpha)=\frac{AdjacentLeg}{Hypotenuse}$

Where:

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Substituting:

$Cosine(x)=\frac{12}{13}$

Clearing x we have:

$x =Cosine^{-1}(\frac{12}{13})$

Thus, the equation is: $x =Cosine^{-1}(\frac{12}{13})$

Answer:

$x =Cosine^{-1}(\frac{12}{13})$

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3 years ago

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Answer:
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Explanation

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3 years ago

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How to write 0.624 in expanded form

GalinKa [24]

Answer:

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Step-by-step explanation:

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3 years ago

Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

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The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) 50% of sales made by Kayla :

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) Spread of the middle 50% of sales :

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

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Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

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Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

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