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Sever21 [200]
3 years ago
14

HELP❕❗

Mathematics
1 answer:
ella [17]3 years ago
4 0

Option B

\frac{a^2b^7c^2}{a^2c^2} = b^7

<em><u>Solution:</u></em>

Given that, we have to simplify the given expression

Given expression is:

\frac{a^2b^7c^2}{a^2c^2}

We can simplify the expression by cancelling the common terms in numerator and denominator

Take the common terms out in given expression

\frac{a^2b^7c^2}{a^2c^2} = \frac{a^2c^2(b^7)}{a^2c^2}

Cancel the common terms in numerator and denominator

\frac{a^2b^7c^2}{a^2c^2} = \frac{a^2c^2(b^7)}{a^2c^2} = b^7

<em><u>Thus the simplified form of given expression:</u></em>

\frac{a^2b^7c^2}{a^2c^2}=b^7

Thus option B is correct

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(X-7)(3x+2) need answer!!
grin007 [14]

Answer: the answer is

=3x^{2}−19x−14  

Step-by-step explanation:  (x−7)(3x+2)

=(x+−7)(3x+2)

=(x)(3x)+(x)(2)+(−7)(3x)+(−7)(2)

=3x2+2x−21x−14

=3x2−19x−14

7 0
4 years ago
James divided the candy bar<br>into 4 parts.<br>He gave 1 part to his friend.​
photoshop1234 [79]

Answer:

If he gave 1 part to his friend then he will have 3 parts left. Is that what you needed help on?

7 0
3 years ago
Choose the fraction that has not been reduced to simplest form.
Gennadij [26K]

We are required to choose the fraction that has not been reduced to simplest form

The fraction that has not been reduced to simplest form is 19/38 and 10/18

1. 21 / 34 is in its simplest form

factors of 21 = 1, 7 and 21

factors of 34 = 1, 2, 17 and 34

No common factor of 21 and 34 except 1

2. 15/16

factors of 15 = 1, 3, 5, 15

Factors of 16 = 1, 2, 4, 8 and 16

No common factor of 15 and 16 except 1

3. 19/38

factors of 19 = 1, 19

factors of 38 = 1, 2, 19 and 38

divide both numerator and denominator by 19

So,

19 / 38 = 1/2

4. 10/18

factors of 10 = 1, 2, 5 and 10

factors of 18 = 1, 2, 3, 6, 9 and 18

So,

10/18

divide both numerator and denominator by 2

= 5/9

Read more:

brainly.com/question/18069

7 0
3 years ago
I'm having trouble in this one, Please help me
mars1129 [50]

Answer:

a. -2/12

b. -0.1

c. 1/9

Step-by-step explanation:

-2/12 = -1/6 < -1/8

-0.1 = -1/10 > -1/8

and 1/9 is the only positive fraction, making it simpler to place.

8 0
3 years ago
A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to mo
den301095 [7]

This question is incomplete, the complete question;

A highway department executive claims that the number of fatal accidents which occur in her state does not vary from month to month. The results of a study of 193 fatal accidents were recorded. Is there enough evidence to reject the highway department executive's claim about the distribution of fatal accidents between each month? Month Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec Fatal Accidents 11 13 22 11 15 29 15 9 13 15 22 18

Step 10 of 10 : State the conclusion of the hypothesis test at the 0.1 level of significance.

Answer: H₀ : The distribution of fatal accidents between each month is same

Step-by-step explanation:

H₀ : The distribution of fatal accidents between each month is same

H₁ : The distribution of fatal accidents between each month is different

Let the los be alpha 0.10

given data ;

       Observed    Expected  

Mon   Freq (Oi)   Freq Ei       (Oi-Ei)^2 /Ei

Jan      11    16.0833        1.606649

Feb      13    16.0833        0.591105

Mar      22    16.0833        2.176598

Apr       11    16.0833        1.606649

May     15    16.0833        0.072971

Jun     29    16.0833        10.373489

Jul     15    16.0833        0.072971

Aug       9    16.0833        3.119603

Sep      13    16.0833        0.591105

Oct      15    16.0833        0.072971

Nov      22    16.0833        2.176598

Dec      18    16.0833       0.228411

Total:   193     93                22.689119

Expected Freq ⇒ 193 / 12 = 16.08333

Test Statistic, x² : 22.6891

Num Categories: 12

Degrees of freedom: 12 - 1 = 11

Critical value X² : 24.725

P-Value: 0.0195

since Chi-square value < Chi-square critical value

and P-value > alpha 0.01 so we accept H₀

Therefore we conclude that the distribution of fatal accidents between each month is same

7 0
3 years ago
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