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Inessa [10]
3 years ago
15

You new motorcycle weighs 2540 n. the acceleration of gravity is 9.8 m/s 2 . what is its mass? answer in units of kg.

Physics
1 answer:
Fed [463]3 years ago
7 0
1 N = 1 kgm/s²
1 N / (1m/s²) = 1 kg 
2540 N / (9,8 m/s²) = 259,18 kg
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Antonina throws a coin straight up from a height of
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Answer:

s=vt-\frac{1}{2}gt^2

Explanation:

We could use the following suvat equation:

s=vt-\frac{1}{2}gt^2

where

s is the vertical displacement of the coin

v is its final velocity, when it hits the water

t is the time

g is the acceleration of gravity

Taking upward as positive direction, in this problem we have:

s = -1.2 m

g=-9.8 m/s^2

And the coin reaches the water when

t = 1.3 s

Substituting these data, we can find v:

v=\frac{s}{t}+\frac{1}{2}gt=-\frac{1.2}{1.3}+\frac{1}{2}(-9.8)(1.3)=-7.3 m/s

where the negative sign means the direction is downward.

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3 years ago
Explain how wavelength and frequency are important in determining the type of light.
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It is important to note that the electromagnetic spectrum has a variety of wavelength and frequency of light in it. Some lights we can see, while others are not visual to our naked eye. It is actually very important to determine the kind of light as different lights have different wavelengths and frequencies. some lights are of very high frequency like the gamma rays, while others are of far lower frequency. <span />
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Two 2.0 cm * 2.0 cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 V battery. a. What
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Answer: a) 31.86 *10^-12 C=31.86 pC; b) 18 V

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C=Q/V where C is equal to C=εo*A/d where A and D are the area and the separation between the plates.

also we have

Q=C*V=ε(o*A/d)*V=(8.85*10^-12*0.02*0.02/1*10^-3)*9=31.86*10^-12 C=31.86pC

Then if the plates apart to a new spacing of 2.0 mm the new capacitance is equal

Cnew=εo*A/2*d so Cnew =Cinitial/2

then Cnew =Q/Vnew (Q is constant after disconnection to the battery)

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5 0
4 years ago
A ball is kicked on a planet the size of Earth but with twice the acceleration due to gravity. If the maximum height of the ball
USPshnik [31]

Answer:

The value t = 1.995 \  s

Explanation:

From the question we are told that

The acceleration due to gravity is a = 2g

The maximum height is h= 39 m

Generally from the kinematic equation

             s =  ut + \frac{1}{2} at^2

Here u  is the velocity of the ball at maximum height before it start falling and the value is  0 m/s

So

            39 =  0* t + \frac{1}{2} (2g)t^2

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t = 1.995 \  s

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4 years ago
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