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Semmy [17]
3 years ago
11

Which element is LEAST likely to react with Magnesium?

Physics
1 answer:
salantis [7]3 years ago
6 0

Answer:

my only true question is b

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How do the prefixes micro,<br> nano and pico relate to each<br> other?
In-s [12.5K]

Answer:

because they are same and their properties

8 0
3 years ago
What does the vibrating object do to the air particles around it ?
Westkost [7]

Answer:

When an object vibrates, it causes movement in surrounding air molecules. These molecules bump into the molecules close to them, causing them to vibrate as well. This makes them bump into more nearby air molecules.

7 0
3 years ago
a length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be
Natali [406]
The equivalent resistance of n resistors connected in parallel is given by
\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} (1)

In our problem, the resulting resistance of the 5 pieces connected in parallel is R_{Eq}=2.00 \Omega, and since the 5 pieces are identical, their resistance R is identical, so we can rewrite (1) as
\frac{1}{R_{Eq} }= \frac{1}{2 \Omega}= \frac{1}{R}+ \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   =  \frac{5}{R}
From which we find R= 5 \cdot 2 \Omega = 10 \Omega.

So, each piece of wire has a resistance of 10 \Omega. Before the wire was cut, the five pieces were connected as they were in series. The equivalent resistance of a series of n resistors is given by
R_{Eq}=R_1 + R_2 + ...+R_n
So if we apply it at our case, we have
R_{eq}=R+R+R+R+R=5 R= 5\cdot 10 \Omega= 50 \Omega

therefore, the resistance of the original wire was 50 \Omega.
5 0
3 years ago
The self inductance relates the magnetic flux linkage to the current through the coil. Calculate the self inductance L in units
Katen [24]

Answer:

Self inductance, L=127\ \mu H

Explanation:

It is given that,

Length of the coil, l = 5 cm = 0.05 m

Area of cross section of the coil, A=3\ cm^2=0.0003\ m^2

Number of turns in the coil, N = 130

The self inductance relates the magnetic flux linkage to the current through the coil and it is given by :

L=\dfrac{\mu_oN^2A}{l}

L=\dfrac{4\pi \times 10^{-7}\times (130)^2\times 0.0003}{0.05}

L = 0.000127 Henry

or

L=127\ \mu H

So, the self inductance of the coil is 127 microhenry. Hence, this is the required solution.

6 0
4 years ago
The watt is a unit of potential energy.<br> True or False?
ryzh [129]
The best and most correct answer among the choices provided by the question is FALSE<span>.
</span>
Watt is the unit of POWER. <span>Power is the work done in a unit of time.</span>

Hope my answer would be a great help for you.    
If you have more questions feel free to ask here at Brainly.
7 0
3 years ago
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