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allsm [11]
3 years ago
12

Consider an ideal spring, with spring constant k, which is oriented along an x-axis. one end of the spring is fixed, and the fre

e end is located at x = 0 when the spring is neither stretched nor compressed. an object having a mass m is attached to the free end of the spring. consider an action in which the free end of the spring is moved from an initial position xi to a final position xf. the work done by the spring (and on the object attached to the free end) during this action is given by
Physics
1 answer:
Blizzard [7]3 years ago
5 0
The spring is neither stretched nor compressed. an object having a mass m is attached to the free end of the spring. consider an action
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Explanation :

Dispersion forces are also known as London dispersion forces. It is the weakest force. Also, it is the part of the Van der Waals forces.

(1) This force is exhibited by all atoms and molecules.

(2) These forces are the result of the fluctuations in the electron distribution within molecules or atoms. Due to these fluctuations, the electric field is created. The magnitude of this force is explained in terms of Hamaker constant 'A'.

(3) Dispersion forces result from the formation of instantaneous dipoles in a molecule or atom. When electrons are more concentrated in a place, instantaneous dipoles formed.

(4) Dispersion force magnitude depends on the amount of surface area available for interactions. If the area increases, the size of the atom also increase. As a result, stronger dispersion forces.

So, the false statement is "Dispersion forces always have a greater magnitude in molecules with a greater molar mass".  

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