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fiasKO [112]
3 years ago
14

Both coordinates of a point in the coordinate

Mathematics
1 answer:
iVinArrow [24]3 years ago
8 0
The answer is quadrant 2
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In circle C, what is the value of X?
solong [7]
The answer should be 112 degrees
7 0
3 years ago
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The volume of a CONE-shaped hole is 75pi ft cubed. If the hole is 9 feet deep, what is the radius of the hole?
Arturiano [62]

Answer:

The radius of hole is 5 feet

Step-by-step explanation:

Depth of conical hole = 9 feet

Let the radius of hole be r

Volume of conical hole =\frac{1}{3} \pi r^2 h

So, Volume of conical hole =\frac{1}{3} \pi \times r^2 \times 9

We are given that volume of a CONE-shaped hole is 75pi ft cubed.

So,\frac{1}{3} \pi \times r^2 \times 9=75 \pi

\frac{1}{3} \times r^2 \times 9=75

r^2=\frac{75 \times 3}{9}

r=\sqrt{\frac{75 \times 3}{9}}

r=5

Hence The radius of hole is 5 feet

6 0
3 years ago
The length of a rectangle is 5 inches shorter than 3 times the width. Which expression represents the length of the rectangle in
Karo-lina-s [1.5K]

Answer:

The answer is 3w-5

Step-by-step explanation:

First you would have to figure out what 3 times the width is which would be the 3w part then to fine the length you would subtract 5 since it is 5 inches shorter

6 0
3 years ago
Read 2 more answers
1. If a polynomial of Degree 4 has an imaginary zero at -2i and a real zero at 5, how many imaginary zeros does it have?
Vadim26 [7]

Answer:

Complex roots for polynomials equations will always come in conjugate pairs.  Since 1-2i is a root, 1+2i will also be a root.  (Just switch the sign of the imaginary part to its opposite.)

Step-by-step explanation:

So far we have 1-2i and 1+2i as roots.  We need two more to make a 4th degree polynomial.

x=1 with multiplicity of 2 means that we count the root twice when we write down the polynomial: (x - 1)(x - 1) = (x - 1)2

Putting it all together, we can construct our polynomial of degree 4 as

y = f(x) = (x - 1)(x - 1)[x - (1-2i)][x - (1+2i)]

Multiply the factors (FOIL):

[x - (1-2i)][x - (1+2i)] =

x2 - (1+2i)x - (1-2i)x + (1-2i)(1+2i) =

x2 - x - 2ix - x + 2ix + (1 + 2i - 2i + 4) =

x2 - 2x + 5

(x - 1)(x - 1) = x2 - x - x + 1 = x2 - 2x + 1

Now multiply the two underlined expressions:

y = (x2 - 2x + 5)(x2 - 2x + 1)

= x4 - 2x3 + 5x2 - 2x3 + 4x2 - 10x + x2 - 2x + 5  by multiplying term by term

= x4 - 4x3 + 10x2 -12x + 5 by collecting like terms.

4 0
2 years ago
If f(x) = 3x-2 and g(x) = 2x + 1 find (f-g)(x)
Marat540 [252]

Answer:

x-3

Step-by-step explanation:

f(x) = 3x-2

g(x) = 2x + 1

(f-g)(x) = 3x-2 - (2x+1)

Distribute the minus sign

          =3x-2-2x-1

Combine like terms

        = 3x-2x-2-1

        =x-3

6 0
3 years ago
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