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MAVERICK [17]
3 years ago
8

PLEASE HELP MEEEEEE PLEASEEEEEEEE!!!!!! IM TIMED

Mathematics
2 answers:
kotykmax [81]3 years ago
6 0

Answer: -23

Step-by-step explanation:

Maurinko [17]3 years ago
5 0

Answer:

b. 17

Step-by-step explanation:

Because five hours later from 6:00 AM is 11:00 AM, all you have to do is add -3+20, which equals 17.

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Neal decides to sell his concert tickets to a sold- out show. He paid 90$ for the pair but believes he can sell them for 150% of
Pie

Answer:

Neal thinks that he can sell the tickets for $135.

Step-by-step explanation:

Original price at which Neal bought the tickets = $90

If he expects to sell them at 150% of the original,

150% as a decimal = 150/100 = 1.5

the new resale price = 1.5* $90

                                   = $135

Therefore, Neal thinks that he can sell the tickets for $135.

5 0
3 years ago
If Sam kicks a soccer ball that has a mass of 10 kg with an acceleration of 22 meters per second squared, what is the force he k
MrMuchimi

Answer:

220 i think but im not sure

Step-by-step explanation:

4 0
3 years ago
A is the midpoint of line segment PT if PA is 5/3x-2 and TA is 4x-37. What is PT
Afina-wow [57]
The answer is 46
Since A is the midpoint of PA and TA you set both equations to equal each other to find x .
5/3x-2=4x-37
x=15
Then plug in 15 for x
4(15)-37=23
Since PT in both segment added together
23+23 =46
6 0
3 years ago
Which one? Helppppppp
Nat2105 [25]

Answer:

second one

Step-by-step explanation:

7 0
3 years ago
For BRAINLIEST:Finding Critical points & Extreme values. #47 & #61 Please provide a clear explanation that is understand
almond37 [142]
Start with #47.  To find the critical values, you must differentiate this function.  x times (4-x)^3 is a product, so use the product rule.  The derivative comes out to f '(x) = x*3*(4-x)^2*(-1) + (4-x)^3*1 = (4-x)^2 [-3x + 4-x]
Factoring this, f '(x) = (4-x)^2 [-3x+4-x] 
Set this derivative equal to zero (0) and solve for the "critical values," which are the roots of   f '(x) = (4-x)^2 [-3x+4-x].  (4-x)^2=0 produces the "cv" x=4.
[-3x+ (4-x)] = 0 produces the "cv" x=1.   Thus, the "cv" are {4,1}.

Evaluate the given function at x: {4,1}.  For example, if x=1, f(1)=(1)(4-1)^3, or 2^3, or 8.  Thus, one of the extreme values is (1,8).  
5 0
3 years ago
Read 2 more answers
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