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3 years ago

Z-m=z+bx , solve for b

Mathematics

2 answers:

KIM [24]3 years ago

3 0

Answer:

b= (Z-m-z)/(x)

Step-by-step explanation:

Z-m=z+bx

Z-m-z=bx [Transpose z of R.H.S to L.H.S] / [Substract z from L.H.S and R.H.S]

(Z-m-z)/(x)=b [Divide by x on both sides i.e, L.H.S and R.H.S]

b= (Z-m-z)/(x)

Hope this helps you.

Rudik [331]3 years ago

3 0

Answer:

B=m/x

Step-by-step explanation:

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Andrei [34K]

Answer:

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Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

4x+3y+2x-y=C1\\

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4x+2x+3y-y=C1

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So, The result is: C1=6x+2y

Now, We need to solve:

Let R1 represent rectangle 4

x+4y + R1 = 4x+5y

R1=4x+5y-(x+4y)

R1=4x+5y-x-4y

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So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y

Now, We need to solve the equation:

Let C4= Circle 4

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3 years ago

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an

Harrizon [31]

Answer:

$x^{1}$ wives

$x^{2}$ sacks

$x^{3}$ cats

$x^{4}$ kits

Suppose the man in the St. Ives poem has x wives, each wife has x sacks, each sack has x cats, and each cat has x kits. Write an expression using exponents that represents the total number of kits, cats, sacks, and wives going to St .Ives.

Step-by-step explanation:

$x^{1}$ wives

If each of the "x" wives has "x" sacks, so the number of sacks is:

$x^{2}$ sacks

If each of the "x" wives has "x" sacks, and each sack has "x" cats, so the number of cats is:

$x^{3}$ cats

If each of the "x" wives has "x" sacks, and each sack has "x" cats, and each cat has "x" kits, so the number of kits is:

$x^{4}$ kits

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tankabanditka [31]

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