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pav-90 [236]
3 years ago
13

Z-m=z+bx , solve for b

Mathematics
2 answers:
KIM [24]3 years ago
3 0

Answer:

b= (Z-m-z)/(x)

Step-by-step explanation:

Z-m=z+bx

Z-m-z=bx [Transpose z of R.H.S to L.H.S] / [Substract z from L.H.S and R.H.S]

(Z-m-z)/(x)=b [Divide by x on both sides i.e, L.H.S and R.H.S]

b= (Z-m-z)/(x)

Hope this helps you.

Rudik [331]3 years ago
3 0

Answer:

B=m/x

Step-by-step explanation:

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Use the distributive property to express 40 in a different form.
Artemon [7]

Answer:

5(4 + 4)

Step-by-step explanation:

5(4 + 4)

20 + 20

40

Hope this helps!

=)

4 0
3 years ago
The sum of Ellie's age and Genya's age is 60. In six years, Genya will be eight times as old as Ellie. How old is Ellie now?
ArbitrLikvidat [17]

Answer:

<u>2 years old</u>

Step-by-step explanation:

Let Ellie's age ⇒⇒⇒ x

And Genya's age ⇒⇒⇒ y

∵ The sum of Ellie's age and Genya's age is 60

∴ x + y = 60 ⇒ (1)

∵ In six years, Genya will be eight times as old as Ellie

∴ (y + 6) = 8 (x+6)

∴ y + 6 = 8x + 48       subtract 6 from both sides

∴ y = 8x + 42 ⇒ (2)

By substituting from 2 at 1 with the value of y

∴ x + (8x + 42) = 60

∴ 9x = 60 - 42 = 18

∴ x = 18/9 = 2

∴ y = 60 - x = 58

So, Ellie's age now = 2 years old

And Genya's age = 58 years old

6 0
3 years ago
Madison arrived at work at 8:00 AM. She went out for lunch at 11:00 AM. She returned at 12:00 PM and worked until 4:00 PM. How m
goblinko [34]
C-7 hours, 0 minutes because between 8 and 11 are 3 hours and between 12 and 4 are 4 hours. 3+4= 7 hours
8 0
3 years ago
Read 2 more answers
Jake can carry 61/4 pounds of wood in from the barn. His father can carry 1 5/7 times as much as jake.
BigorU [14]
To answer this item, we are to multiply the given amount of wood that Jake can carry which is given to be 6 1/4 by the number of times his father can which is equal to 1 5/7.                x = (6 1/4)(1 5/7)
                x = 75/7
 Thus, Jake's father can carry 10 5/7 pounds of wood. (I've had this question before btw)
3 0
4 years ago
Read 2 more answers
Which of the following is true of the location of an angle, Theta, whose tangent value is - sqrt3/3?
prohojiy [21]

Answer:

Step-by-step explanation:

Keep in mind that the tangent function is negative in Quadrants II and IV.

Of the three possible answers, the 2nd is invalid because the tangent is positive in Q III.

If the reference angle were in Quadrant II and had the value 30° (second possible answer), then the opposite side would be +1, the adjacent side -√3 and the hypotenuse 2.  Based on this, the tangent of theta would be opp / adj, or +1 / (-√3)  or -√3/3.    This is correct.

4 0
4 years ago
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