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Firlakuza [10]
3 years ago
13

Please help me! This is due today

Mathematics
1 answer:
pishuonlain [190]3 years ago
3 0

Answer:

PICTURE IS BLOCKED

Step-by-step explanation:

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3: 0.625

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Step-by-step explanation:

8 0
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Read 2 more answers
If f(×)=2×^2+3, then which of the following represent f(-1)?
eimsori [14]

To find the inverse of this function, we first need to replace f(x) with y.

y = 2x^2 + 3

Now, we swap x and y

x = 2y^2 + 3

Now, we solve for y.

-3

x - 3 = 2y^2

Sqrt both sides.

√(x - 3) = 2y

Divide by 2

√(x - 3)/2 = y

Replace y with f^-1(x)

√(x - 3)/2 = f^-1(x)


Just realized you were asking for f(-1), not f^-1(x)

Feels bad.

f(-1) = 2(-1^2 + 3)

f(-1) = 2(-1^5)

f(-1) = 2(-1)

<u>f(-1) = -2</u>

I'm leaving the original answer in case you also need the inverse function. :)

3 0
3 years ago
Jenna's statistics classes have the following enrollments: section A has 22 students, section B has 38 students, and section c h
Elina [12.6K]

Answer:38%

Step-by-step explanation:

38/100=.38

5 0
3 years ago
Which equation is y = –6x^2 + 3x + 2 rewritten in vertex form? plz help will give
Zigmanuir [339]
Y = –6.x²<span> + 3.x + 2.

Its vertex form is (y-k) = a(x-h)</span>², where the vertex is V(h , k).

Let's calculate k and h from the original function y = - 6.x² + 3.x + 2.

a) the maximum is when f(0) = k→ -6(0)² + 3(0) + 2 , hence k = 2

b) The axis of symmetry is equal to x = -b/2.a:
x= -(3)/2.(-6) → x = 1/4 (1/4 is = h); Now replace k & h in the Vertex form
y-k = a(x-h)²

y- 2 = -6(x-1/4)²




6 0
3 years ago
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