All categories

2 years ago

Tell whether each scale reduces enlarges or preserves the size of an actual object

Mathematics

2 answers:

Rasek [7]2 years ago

8 0

1m to 25 cm is reduces
8 in to 1 ft is enlarges
12 in to 1 ft is preserves

mr_godi [17]2 years ago

4 0

Given:

1 m : 25 cm

8 in : 1 ft

12 in : 1 ft

First, we convert each variable given on the right:

1 m : 0.25 m (this means that 1 meter is made to represent 25 cm)

8 in : 12 feet (this means that 8 in is made to represent 1 feet)

12 in : 12 in (this means that 12 in is made to represent 1 feet)

After converting the variables, we can now know if the ratios are enlargement, reduction or preservation. Therefore:

1 m : 25 cm = Enlarge

8 in : 12 feet = Reduce
12 in = 1 ft = Preserve

You might be interested in

celine mixes raisins and peanuts to make a snack. she uses 0.75 cup raisins for every 0.5 cup peanuts. write a proportion and us

PtichkaEL [24]

Answer:

6.375 cups of raisins

Step-by-step explanation:

The ratio of raisins to peanuts is 3:2. This is because 0.5 divided by 2 and then multiplied by 3 is equal to 0.75.

So to find the number of raisins we need to divide the number of peanuts by 2 and then multiply it by 3:

(4.25 ÷ 2) × 3 = 6.375

4 0

2 years ago

Read 2 more answers

Sunday later my sister clean 1 3/9 hours Monday my mom clean 2 5/6 hours the my bad clean 1 4/2 hours who cleaned the most

ohaa [14]

Answer:

Hermana

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

24. Use the intercepts to graph the equation.

romanna [79]

Answer:

See below ~

Step-by-step explanation:

Finding x-intercept

Take y = 0
2x - 5(0) = 10
2x = 10
x = 5
x-intercept is at (5, 0)

Finding y-intercept

Take x = 0
2(0) - 5y = 10
-5y = 10
y = -2
y-intercept is at (0, -2)

Graph (with points marked)

5 0

1 year ago

Read 2 more answers

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$