17(n+31)=357
distribute:
17n+527=357
-527 -527
17n= -170
÷17 <span>÷17
</span>n=-10
A: negative 10
Formula: V = (2/3) π r 3.
Radius is 3cm.
So, now we can plug it in to solve for the volume.
V = (2/3) π 3^3
First, let's multiply 3^3.
3^3 = 27
Then, 27 x π = 84.82
After, multiply by 2/3.
84.82 x 2/3 = 56.55
Lastly, round 56.55 to the nearest tenth of a cubic centimeter.
56.55 = 56.6
Therefore the volume of a hemisphere with a radius of 3cm is 56.6cm^3.
Solve x(x-5)=0; the roots are 0 and 5.
Draw a number line. Plot 0 and 5 on this line.
Set up 3 intervals, as follows: (-infinity, 0), (0, 5), and (5, infinity).
Now choose a test number from within each interval (e. g., -2, 3, 10).
Subst. each into the inequality x(x-5)

0. In each case, determine whether the inequality is true or false.
Based upon your results here, you should be able to determine on which interval or intervals the inequality is true. Those interval(s) is/are your solution set.
A is the correct answer because he did not ask the whole class.