Answer:
fgh(x)=4
-14
Step-by-step explanation:
when solving composite fuctions we go from the right to the left
meaning we replace the x in the g function with the entire h function
then replace the x in the f function with the entire new g function
h(x)=
g()= -5
f(-5)=4( -5)+6
f(-5)=4 -20+6
fgh(x)=4 -14
The area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6
<h3>Calculating area </h3>
From the question, we are to determine the area of the shaded region
The area of the shaded region = Area of the semicircle - Area of the triangle
First, we will determine the diameter, d, of the semicircle
d² = 3² + 4² (<em>Pythagorean theorem</em>)
d² = 9 + 16
d² = 25
d = √25
d = 5
∴ Diameter of the semicircle is 5
Thus,
Radius, r = 5/2 = 2.5
Now,
Area of the shaded region = 1/2(π×2.5²) - 1/2(3×4)
Area of the shaded region = 1/2(π×6.25) - 1/2(12)
Area of the shaded region = 3.125π - 6
Hence, the area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6
Learn more on Calculating area here: brainly.com/question/14989383
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The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.
Answer:
17/k
Step-by-step explanation:
Quotient means division
17/k
