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Ierofanga [76]
3 years ago
10

Which equation represents a line which is parallel to the line 7y - 4x -14?

Mathematics
1 answer:
jarptica [38.1K]3 years ago
8 0
So the given function is (4/7)x
(4/7) is the slope.
As long as the slope is the same the function will be parallel.
So these examples are parallel:
g(x) = (4/7)x - 10

h(x) = (4/7)x + 122
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If f ( x ) = x 4 + 6 , g ( x ) = x − 5 and h ( x ) = √ x , then f ( g ( h ( x ) ) ) =
zaharov [31]

Answer:

fgh(x)=4\sqrt{x} -14

Step-by-step explanation:

when solving composite fuctions we go from the right to the left

meaning we replace the x in the g function with the entire h function

then replace the x in the f function with the entire new g function

h(x)=\sqrt{x}

g(\sqrt{x})=\sqrt{x} -5

f(\sqrt{x}-5)=4(\sqrt{x} -5)+6

f(\sqrt{x}-5)=4\sqrt{x} -20+6

fgh(x)=4\sqrt{x} -14

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3 years ago
Can y’all help me on question 33?!
Dima020 [189]
The answer is letter A
5 0
3 years ago
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Select the correct answer!<br> Help asap thanks
tester [92]

The area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6

<h3>Calculating area </h3>

From the question, we are to determine the area of the shaded region

The area of the shaded region = Area of the semicircle - Area of the triangle

First, we will determine the diameter, d, of the semicircle

d² = 3² + 4² (<em>Pythagorean theorem</em>)

d² = 9 + 16

d² = 25

d = √25

d = 5

∴ Diameter of the semicircle is 5

Thus,

Radius, r = 5/2 = 2.5

Now,

Area of the shaded region = 1/2(π×2.5²) - 1/2(3×4)

Area of the shaded region = 1/2(π×6.25) - 1/2(12)

Area of the shaded region = 3.125π - 6

Hence, the area of the shaded region is 3.125π - 6. The correct option is E. 3.125π - 6

Learn more on Calculating area here: brainly.com/question/14989383

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7 0
2 years ago
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.

The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or 
range related to a group of data.

They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.

I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.

Large outliers can inflate the value of means, medians and ranges.

Small outliers will invariably deflate the value of means and medians.
3 0
3 years ago
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The quotient of 17 and k
valkas [14]

Answer:

17/k

Step-by-step explanation:

Quotient means division

17/k

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