Answer:
A, (1, 3+1/2)
Step-by-step explanation:
Midpoint formula for reference: m= {(x1 + x2)/2, (y1 + y2)/2}
Plugging in the points we get: m= {(8 - 6)/2, (5 + 2)/2}
Now we simplify using PEMDAS. First step is parentheses.
m= {2/2, 7/2}
Simplifying again (and making 7/2 a mixed number), it becomes
m= {1, 3+1/2}
Hope this helps!
Answer:
Step-by-step explanation:
Volume of tank is 3000L.
Mass of salt is 15kg
Input rate of water is 30L/min
dV/dt=30L/min
Let y(t) be the amount of salt at any time
Then,
dy/dt = input rate - output rate.
The input rate is zero since only water is added and not salt solution
Now, output rate.
Concentrate on of the salt in the tank at any time (t) is given as
Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000
dy/dt= dV/dt × dM/dV
dy/dt=30×y/3000
dy/dt=y/100
Applying variable separation to solve the ODE
1/y dy=0.01dt
Integrate both side
∫ 1/y dy = ∫ 0.01dt
In(y)= 0.01t + A, .A is constant
Take exponential of both side
y=exp(0.01t+A)
y=exp(0.01t)exp(A)
exp(A) is another constant let say C
y(t)=Cexp(0.01t)
The initial condition given
At t=0 y=15kg
15=Cexp(0)
Therefore, C=15
Then, the solution becomes
y(t) = 15exp(0.01t)
At any time that is the mass.
Answer:
StartFraction 16 over negative 3, EndFraction StartFraction negative 16 over 3, and EndFraction Negative (StartFraction 16 over 3 EndFraction)
I hope this helps
Step-by-step explanation:
Answer:
A≈61.94
Just plug it into a calculator
Add 7 and 7 which is 14 and then take it apart because it is an even number
