This question is incomplete, the complete question is;
In a survey, 55% of the voters support a particular referendum. If 40 voters are chosen at random,
find the mean and variance for the number of voters who support the referendum.
Answer:
a) The Mean is 22
b) Variance is 9.9
Step-by-step explanation:
Given that;
55% of the voters support a particular referendum p = 0.55
q = 1 - p = 1 - 0.55 = 0.45
sample size n = 40
a)
Mean = sample size n × p
Mean = 40 × 0.55
Mean = 22
Therefore the Mean is 22
b)
Variance = n × p × q
so we substitute
Variance = 40 × 0.55 × 0.45
Variance = 9.9
Therefore the Variance is 9.9
Answer: A
Step-by-step explanation:
This is because...
1st. Simplify both sides of the equation (distribute the 4 and combine like terms)
6 + -x = 20 + 4x + -4 (distributed 4)
-x + 6 = 4x + 16 (combined like terms)
2nd. Subtract 4x from both sides.
3rd. Subtract 6 from both sides.
4th. Divide both sides by -5.
Answer:
the licorice stick is $1.25 and the candies are $1.00
Answer:
A = 0.7777777777777
B= 0.2424242424
C= 0.2727272727
Step-by-step explanation:
Plz make it brainlist answer
X=-10
by simplifying both sides of the equation then isolating the variable
