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vfiekz [6]
3 years ago
7

Emma is training for a 10-kilometer race. She wants to beat her last 10-kilometer time, which was 1 hour 10 minutes. Emma has al

ready run for 55 minutes. Which inequality can be used to find how much longer she can run and still beat her previous time? (1 hr = 60 min)
70 greater-than 7 minus 55
70 less-than t minus 55
70 less-than-or-equal-to t + 55
70 greater-than t + 55
x + 6 less-than negative 8

x + 4 greater-than-or-equal-to negative 6

x minus 3 greater-than negative 10

x + 5 less-than-or-equal-to negative 4

A
B
C
D
Mathematics
2 answers:
Mandarinka [93]3 years ago
7 0

Answer:

70 > 55 + t

Step-by-step explanation:

Given

Previous\ Time = 1\ hr\ 10\ mins

Current\ Time = 55\ mins

Required

Represent the additional time needed as an inequality

Convert the previous time to minutes

Previous\ Time = 1\ hr\ 10\ mins

Previous\ Time = 1 * 60\ mins + 10\ mins

Previous\ Time = 60\ mins + 10\ mins

Previous\ Time = 70\ mins

Let the additional time be t

<em>This means that she needs to run at least t minutes to beat her previous record</em>

<em />

To beat her previous record, the sum of current time and x must be less than her previous time. i.e.

55 + t < 70

This can be rewritten as:

70 > 55 + t

Mazyrski [523]3 years ago
4 0

Answer:the answer is D

Step-by-step explanation:

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PilotLPTM [1.2K]

Answer:

<h3>The options A),B) and E) are correct</h3><h3>A) The given expression p-\frac{2}{3}p is equivalent to \frac{p}{3}</h3><h3>B) The given expression \frac{p}{3} is equivalent to \frac{p}{3}</h3><h3>E) The given expression \frac{3p}{9} is equivalent to \frac{p}{3}</h3>

Step-by-step explanation:

Given expression is \frac{p}{3}

<h3>To find the equivalent expressions to the given expression :</h3>

A) p-\frac{2}{3}p

Solving the expression p-\frac{2}{3}p

p-\frac{2}{3}p=\frac{p(3)-2p}{3}

=\frac{3p-2p}{3}

=\frac{p}{3}

<h3>∴ p-\frac{2}{3}p=\frac{p}{3}</h3><h3>∴ The given expression p-\frac{2}{3}p is equivalent to \frac{p}{3}</h3>

B) \frac{p}{3}

<h3>∴ The given expression \frac{p}{3} is equivalent to \frac{p}{3}</h3>

E) \frac{3p}{9}

Solving it we get

∴ \frac{3p}{9}=\frac{p}{3}

<h3>∴ The given expression \frac{3p}{9} is equivalent to \frac{p}{3}</h3><h3>  ∴ options A),B) and E) are correct</h3>
5 0
3 years ago
A prism _____ has two congruent, parallel bases. sometimes never always
IrinaVladis [17]
Its Always. They have two congruent sides.











Always                                                           
6 0
3 years ago
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Answer:

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Step-by-step explanation:

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8 0
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aleksandrvk [35]

Answer:

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