Answer:
a) 

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
b) 

So one deviation below the mean we have: (100-68)/2 = 16%
c) 

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Step-by-step explanation:
For this case we have a random variable with the following parameters:

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.
We want to find the following probability:

We can find the number of deviation from the mean with the z score formula:

And replacing we got


And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
For the second case:


So one deviation below the mean we have: (100-68)/2 = 16%
For the third case:

And replacing we got:


For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
There isn't enough info to determine that, I believe. You would need an equation that would allow me to determine the minimum output for an A.
2y + 4 + 5y + 8=
7y + 4 + 8=
7y + 12=
Answer:
f6h40
Step-by-step explanation:
Step 1 :
h23
Simplify ———
f3
Equation at the end of step 1 :
h23
((f9) • ———) • h17
f3
Step 2 :
Multiplying exponential expressions :
2.1 h23 multiplied by h17 = h(23 + 17) = h40
Final result :
f6h40
Answer
C because 2 quarts make's one gallon
Step-by-step explanation: