15.
2 answers:
Answer:
A. 0.3x2
Step-by-step explanation:
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex:
(
0
,
0
)
Focus:
(
0
,
0.8
¯
3
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
0.8
¯
3
x
y
−
2
1.2
−
1
0.3
0
0
1
0.3
2
1.2
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Down
Vertex:
(
0
,
0
)
Focus:
(
0
,
−
1
16
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
1
16
x
y
−
2
−
16
−
1
−
4
0
0
1
−
4
2
−
16
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Down
Vertex:
(
0
,
0
)
Focus:
(
0
,
−
5
16
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
5
16
x
y
−
2
−
16
5
−
1
−
4
5
0
0
1
−
4
5
2
−
16
5
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex:
(
0
,
0
)
Focus:
(
0
,
3
4
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
3
4
x
y
−
2
4
3
−
1
1
3
0
0
1
1
3
3
3
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The horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m
<u>Explanation:</u>
Given:
h(x) = -0.026x² + 0.563x + 3
where,
h(x) is the height of the water
Initial speed, u = 14m/s
angle, θ = 30°
(a)
Horizontal distance = ?
h(x) = ax² + bx + c
the vertex is found at x = -b/2a
where,
x = distance to the maximum height
As compared to the equation given:
a = -0.026
b = 0.563
Thus,
Therefore, horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m