15.
2 answers:
Answer:
A. 0.3x2
Step-by-step explanation:
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex:
(
0
,
0
)
Focus:
(
0
,
0.8
¯
3
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
0.8
¯
3
x
y
−
2
1.2
−
1
0.3
0
0
1
0.3
2
1.2
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Down
Vertex:
(
0
,
0
)
Focus:
(
0
,
−
1
16
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
1
16
x
y
−
2
−
16
−
1
−
4
0
0
1
−
4
2
−
16
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Down
Vertex:
(
0
,
0
)
Focus:
(
0
,
−
5
16
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
5
16
x
y
−
2
−
16
5
−
1
−
4
5
0
0
1
−
4
5
2
−
16
5
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex:
(
0
,
0
)
Focus:
(
0
,
3
4
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
3
4
x
y
−
2
4
3
−
1
1
3
0
0
1
1
3
3
3
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Answer:
95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].
Step-by-step explanation:
We are given that for the 69 second-year students in the study at the university, the sample mean procrastination score was 41.00 and the sample standard deviation was 6.89.
Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;
P.Q. = ~
where, = sample mean procrastination score = 41
s = sample standard deviation = 6.89
n = sample of students = 69
= population mean estimate
<em>Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.</em>
So, 95% confidence interval for the true mean, is ;
P(-1.9973 < < 1.9973) = 0.95 {As the critical value of t at 68 degree
of freedom are -1.9973 & 1.9973 with P = 2.5%}
P(-1.9973 < < 1.9973) = 0.95
P( <
<
) = 0.95
P( <
<
) = 0.95
<u>95% confidence interval for </u> =[
,
]
= [ ,
]
= [39.34 , 42.66]
Therefore, 95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].