15.
2 answers:
Answer:
A. 0.3x2
Step-by-step explanation:
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex:
(
0
,
0
)
Focus:
(
0
,
0.8
¯
3
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
0.8
¯
3
x
y
−
2
1.2
−
1
0.3
0
0
1
0.3
2
1.2
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Down
Vertex:
(
0
,
0
)
Focus:
(
0
,
−
1
16
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
1
16
x
y
−
2
−
16
−
1
−
4
0
0
1
−
4
2
−
16
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Down
Vertex:
(
0
,
0
)
Focus:
(
0
,
−
5
16
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
5
16
x
y
−
2
−
16
5
−
1
−
4
5
0
0
1
−
4
5
2
−
16
5
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex:
(
0
,
0
)
Focus:
(
0
,
3
4
)
Axis of Symmetry:
x
=
0
Directrix:
y
=
−
3
4
x
y
−
2
4
3
−
1
1
3
0
0
1
1
3
3
3
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The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.