You have to go on a computer or phone and find how to draw a cube you did kind of good
Answer:
DECOMPOSITION
Explanation:
Examples: 2 H2O → 2 H2 + O2 CaCO3 → CaO + CO2 Decompositions are generally the opposite (reverse) of combination reactions, and they usually involve oxidation and reduction (but not in the last example).
Explanation:
It is known that the relation between pH and
is as follows.
pH = ![pK_{a} + log \frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
and, ![pK_{a} = -log K_{a}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20-log%20K_%7Ba%7D)
Hence, first we will calculate the value of
as follows.
![pK_{a} = -log K_{a}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%3D%20-log%20K_%7Ba%7D)
=
= 4.75
Now, we will calculate the value of pH as follows.
pH = ![pK_{a} + log \frac{[\text{sodium acetate}]}{\text{acetic acid}}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5B%5Ctext%7Bsodium%20acetate%7D%5D%7D%7B%5Ctext%7Bacetic%20acid%7D%7D)
=
= 4.75 + (-0.677)
= 4.07
Therefore, we can conclude that the pH of given solution is 4.07.
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Answer:
0.500 M
Explanation:
The balanced equation for the neutralization reaction is as follows
NaOH + HCl —> NaCl + H2O
Molar ratio of NaOH to HCl is 1:1
Number of moles of NaOH reacted is equal to the number of HCl moles
We can use the following equation
c1v1 = c2v2
Where c1 is concentration and v1 is volume of HCl
c2 is concentration and v2 is volume of NaOH
Substituting the values
1.00 M x 10.0 mL = c2 x 20.0 mL
c2 = 0.500 M
Concentration of NaOH is 0.500 M