Answer:
See attachment.
Explanation:
Mono-substituted cyclohexanes are more stable with their substituents in an equatorial position. However, with poly-substituted cyclohexanes, the situation is more complex since the steric effects of all substituents have to be taken into account. In this case, you can see that <u>the interconversion is shifted towards the conformation in the bottom because there is less tension between the substituents</u>.
Answer:
Function A: +3
Function B: +2
y intercept is greater in Function B, the value is 16
Explanation:
The ph of a saturated solution of Ca(OH)2 is 12.35
CALCULATION:
For the reaction
Ca(OH)2 → Ca2+ + 2OH-
we will use the Ksp expression to solve for the concentration [OH-] and then use the acid base concepts to get the pH:
Ksp = [Ca2+][OH-]^2
The listed Ksp value is 5.5 x 10^-6. Substituting this to the Ksp expression, we have
Ksp = 5.5 x 10^-6 = (s) (2s)^2 = 4s^3
s3 = 5.5x10^-6 / 4
Taking the cube root, we now have
s = cube root of (5.5x10^-6 / 4)s
= 0.01112
We know that the value of [OH-] is actually equal to 2s:
[OH-] = 2s = 2 * 0.01112 = 0.02224 M
We can now calculate for pOH:
pOH = - log [OH-]
= -log(0.02224)
= 1.65
Therefore, the pH is
pH = 14 - pOH
= 14 - 1.65
= 12.35
The empirical formula is C₂H₆O.
We must calculate the <em>masses of C, H, and O</em> from the masses given.
<em>Mass of C</em> =38.20 g CO₂ × (12.01 g C/44.01 g CO₂) = 10.424 g C
<em>Mass of H</em> = 23.48 g H₂O × (2.016 g H/18.02 g H₂O) = 2.6268 g H
<em>Mass of O</em> = Mass of compound - Mass of C - Mass of H
= (20.00 – 10.424 – 2.6268) g = 6.9487 g
Now, we must <em>convert these masses to moles</em> and <em>find their ratios</em>.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u>Integers</u>
C 10.424 0.8680 1.999 2
H 2.6268 2.606 6.001 6
O 6.9487 0.4343 1 1
The empirical formula is C₂H₆O.
