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liraira [26]
3 years ago
12

Refer to the table . Which plants would most likely be found in the rain forest

Chemistry
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer: I would think 4 because there are plants every were there like literally there is lots of flowers green bushes trees vines there's lots of wonderful beautiful stuff there so I think the number 4

Explanation:

A rainforest orchid. Orchids are very common plants in the tropical rainforest. The Amazon Rainforest itself is home to more than 40,000 plant species! The most common tree in the Amazon Rainforest is the açai here are some of the plants there are there

Bromeliads Plant (Bromeliaceae)

Emergent Plant

Heliconia Flower (Lobster-Claw)

Orchid Plant

Passion flowers (Passiflora spp.)

Lianas

Vines

Rubber Tree (Hevea brasiliensis)

Cacao (Theobroma cacao)

Giant Water Lilies (Victoria amazonica)

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6 How many moles are in a 321 g sample of magnesium?
Tatiana [17]

Answer:

13.4mol of Mg

Explanation:

Given parameters:

Mass of magnesium = 321g

Unknown:

Number of moles  = ?

Solution:

The number of moles of a substance is given as;

  Number of moles  = \frac{mass}{molar mass}  

 Molar mass of Mg = 24g/mol

 Insert the parameters and solve;

        Number of moles  = \frac{321}{24}   = 13.4mol of Mg

3 0
3 years ago
3CuSO4
Alex73 [517]

Answer:

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Explanation:

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5 0
3 years ago
What is biological difference ​
topjm [15]

Answer:

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Explanation:

4 0
3 years ago
Extra Stoichiometry Practice
Irina-Kira [14]

Answer: 50. 4g

Explanation:

First calculate number of moles of aluminium in 38.8g

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By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.

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8 0
3 years ago
What is the reducing agent in the reaction below?
frez [133]
Option (a) is correct.
A reducing agent is the one which loses electrons to other substance and an oxidizing agent is one which accepts electrons. 
Here, In CrO_{3}, Cr has oxidation number 6+  in the L.H.S of the equation, but on R.H.S its oxidation number is 0 i.e. it Cr has gained electrons such that total charge is 0.
And the oxidation state of Al in the left-hand side of equation is 0 and in right-hand side, it is +6.i.e. it has donated its electrons to Cr. 

Hence, Cr is the oxidizing agent and Al is the reducing agent. 
4 0
4 years ago
Read 2 more answers
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