Answer:
The time required to melt the frost is 3.25 hours.
Explanation:
The time required to melt the frost dependes on the latent heat of the frost and the amount of heat it is transfered by convection to the air .
The heat transferred per unit area can be expressed as:
being hc the convective heat transfer coefficient (2 Wm^-2K^-1) and ΔT the difference of temperature (20-0=20 °C or K).
If we take 1 m^2 of ice, with 2 mm of thickness, we have this volume
The mass of the frost can be estimated as
Then, the amount of heat needed to melt this surface (1 m²) of frost is
The time needed to melt the frost can be calculated as
Answer:
a delayed neutron is a neutron emitted after a nuclear fission event, by one of the fission products (or actually, a fission product daughter after beta decay), any time from a few milliseconds to a few minutes after the fission event.
Explanation:
Answer:
(f - g)(2) = -6
Step-by-step explanation:
(f - g)(2) = (-2x + 8) - 5x, where x=2
= (-2(2) + 8) - 5(2)
= (-4 + 8) - 10
= 4 - 10
= -6
(f - g)(2) = -6
Answer:
Mass FeCl2 = 0.0333g
Mass CrCl2 = 0.9961g
Explanation:
To solve this problem. The first equation we can write is:
Mass FeCl2 + Mass CrCl2 = 1.0294g <em>(1)</em>
Now, the Chlorides of FeCl2 and CrCl2 react producing 2.3609g of AgCl
Using molar mass of these species (126.75g/mol, 122.9g/mol, 143.32g/mol, respectively), you can write the equation:
2Mass FeCl2 / 126.75 + 2Mass CrCl2 / 122.9 = 2.3609/143.32
<em>That is: Moles Chloride before = Moles Chloride in AgCl after reaction</em>
7.8895x10⁻³Mass FeCl2 + 0.0162734MassCrCl2 = 0.016473 <em>(2)</em>
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Replacing (1) in (2):
7.8895x10⁻³ (1.0294g - MassCrCl2) + 0.0162734MassCrCl2 = 0.016473
8.12145x10⁻³ -7.8895x10⁻³MassCrCl2 + 0.0162734Mass CrCl2 = 0.016473
8.3839x10⁻³ MassCrCl2 = 8.35155x10⁻³
Mass CrCl2 = 0.9961g
And:
Mass FeCl2 = 1.0294g - 0.9961g
Mass FeCl2 = 0.0333g