Do you need to find what t is? If so, do 300 divided by 60 to get the t isolated. which is, 5.
you can check by doing 60*5 which is 300
Cost of fence for a meter = 6.88
For 32.5 m, it would be = 6.88 * 32.5 = 223.6
D)223.60 is answer
The formula you can use for the withdrawals is that of an annuity. You have interest adding to the balance at the same time withdrawals are reducing the balance.
The formula I remember for annuities is
.. A = Pi/(1 -(1 +i)^-n) . . . . . i is the interest for each of the n intervals; A is the withdrawal, P is the initial balance.
This formula works when the withdrawal is at the end of the interval. To find the principal amount required at the time of the first withdrawal, we will compute for 3 withdrawals and then add the 7500 amount of the first withdrawal.
.. 7500 = P*.036/(1 -1.036^-3)
.. 7500 = P*0.357616
.. 7500/0.0347616 = P = 20,972.20
so the college fund balance in 4 years needs to be
.. 20,972.20 +7,500 = 28,472.20
Since the last payment P into the college fund earns interest, its value at the time of the first withdrawal is P*1.036. Each deposit before that earns a year's interest, so the balance in the fund after 4 deposits is
.. B = P*1.036*(1.036^4 -1)/(1.036 -1)
We want this balance to be the above amount, so the deposit (P) is
.. 28,472.20*0.036/(1.036*(1.036^4 -1)) = 6510.62
You must make 4 annual deposits of $6,510.62 starting now.
Answer:
The answer is below
Step-by-step explanation:
Speed is the ratio of distance covered to the time taken. Speed is given by the formula:
speed = distance / time.
Let us assume the spider walking speed is x and its running speed is y.
If the spider walks for 10 seconds and runs for 9 seconds, she travels 85m. distance = speed * time, hence:
Total distance = distance covered walking + distance covered running
10x + 9y = 85 (1)
Also if she walks for 30 seconds and runs for 2 seconds, she travels 130m. Hence:
30x + 2y = 130 (2)
Solving equation 1 and 2 simultaneously by mutiplying equation 1 by 3 and subtracting equation 2 from the result:
25y = 125
y =5 m/s
Put y = 5 in eqn. 2
30x + 2(5) = 130
30x = 120
x = 4 m/s
The spider walks at 4 m/s and runs at 5 m/s
