Answer:
Compressions and Rarefactions
<em>A vibrating tuning fork is capable of creating such a longitudinal wave. As the tines of the fork vibrate back and forth, they push on neighboring air particles. The forward motion of a tine pushes air molecules horizontally to the right and the backward retraction of the tine creates a low-pressure area allowing the air particles to move back to the left.</em>
Explanation:
These regions are known as compressions and rarefactions respectively. The compressions are regions of high air presure while the rarefactions are regions of low air pressure.
<em>Sound waves can also be shown in a standard x vs y graph, as shown here. This allows us to visualise and work with waves from a mathematical point of view. The resulting curves are known as the "waveform" (i.e. the form of the wave.) The wave shown here represents a constant tone at a set frequency.</em>
Answer:
The one which has a Frequency of 140Hz.
Answer:
Answer would be A
Explanation:
If you cannot read it A is
warm, moist air rises
Answer:
Mesopelagic zone
Explanation:
The Mesopelagic zone, also referred to as the Twilight zone, is the second oceanic zone from the top, lying just bellow the Epipelagic zone. It is occupying the waters at depths between 200 meters and 1,000 meters. The sunlight is only managing to reach the top few meters of this zone, while the rest is not receiving any sunlight, thus this zone is not supporting the plant species because they need sunlight for the process of photosynthesis. There are lot of animal species that live in this zone though, and they are ll very well adapted for it, often having hard shells or heavily scaled bodies, larger lungs and heart, and very well developed gills. Some of the animals that live in here are the crabs and the clams. They have developed all the needed characteristics to live in this zone. Because they are prey to lot of larger animals, both the crabs and the clams have started to use the soft sediments at the bottom as cover, digging themselves below it, and mostly managing to evade trouble and end up as food for the other species.
Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
