For this case we have that by definition, the distance between two points is given by:

We have to:

Substituting:


ANswer:

Step-by-step explanation:
It came from nowhere. It makes no sense to add up the balance numbers. To illustrate, let's use a different example:
![\left[\begin{array}{cc}Spend&Balance\\100&400\\100&300\\100&200\\100&100\\100&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DSpend%26Balance%5C%5C100%26400%5C%5C100%26300%5C%5C100%26200%5C%5C100%26100%5C%5C100%260%5Cend%7Barray%7D%5Cright%5D)
Adding up the money you spent, and you get $500. Add up the balances, and you get $1000. But why would you add the balances? The 300 in the second line is included in the 400 in the first line. You can't add them together. You'd be counting the 300 twice.
Each element is 2/3 times the previous one, so that's a geometric sequence.
6×(2/3)=4, 4×(2/3)=8/3, 8/3×(2/3)=16/9, 16/9×(2/3)=32/27
Answer: 6, 4, 8/3, 16/9, 32/27
Step-by-step explanation:
i = interest 3% for 30 years
This is a simple dynamical system for whom the the solutions are given as
](https://tex.z-dn.net/?f=S%3DR%5B%5Cfrac%7B%28i%2B1%29%5En-1%7D%7Bi%7D%5D%28i%2B1%29)
putting values we get
S=2000[\frac{(1.03)^{30}-1}{0.03}](1.03)
= $98005.35
withdrawal of money takes place from one year after last payment
To determine the result we use the present value formula of an annuity date

we need to calculate R so putting the values and solving for R we get
R= $6542.2356
Please show a picture of the diagram.