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3 years ago

Divide 28 into 2 groups so the ratio is 3 to 4

Mathematics

1 answer:

emmasim [6.3K]3 years ago

8 0

3 4

Left side gets 12.

Right side gets 16.

12+16=28 in total.

When you're thinking of ratios, you have to think of rounds. Let's say I want to distribute apples... In Round 1, I'm going to give myself 1 apple and give you 2 apples. After Round 1, three apples have been distributed in total. Now, if I repeat the same pattern of distribution 1:2, after Round 2 I should have 2 apples whilst you have 4. After Round 2 a total of 6 apples would have been distributed.If the ratio is 3 to 4 - imagine there are 7 groups total, and one person gets 3 of the 7 and the other person gets 4 of the 7.

____________________________________________
If 28 is divided into 7 groups, each group has 4 cans.

One person gets 3 groups = 4*3 = 12 cans
The other gets 4 groups = 4*4* = 16 cans

This way is easier for me to do, but go with whatever works for you :)

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stiv31 [10]

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3 years ago

Pump 1 can empty a pool in 8 hours while Pump 2 can empty the same pool in 9 hours. If the two pumps worked together, how long w

yan [13]

Rate of pump A: 1/8 of a pool per hour
Rate of pump B: 1/9 of a pool per hour
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So if they work together, the two pumps have a combined rate of 25/72 of a pool per hour (i.e in one hour, the two pumps will empty 25/72 of the pool)

But we want to empty ONE pool (not 25/72 of one). So we need to multiply 25/72 by some number x to get 1.

Now solve for x
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7 0

3 years ago

A spinner with 12 equal sections is spun. Each section is numbered 1 to 12. What Is the probability of landing on an odd number.

Bezzdna [24]

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Step-by-step explanation:

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3 years ago

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Vikki [24]

Answer:

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3 0

2 years ago

Read 2 more answers

Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago