Answer:
A. 50, 48, 14.
Step-by-step explanation:
The measurements of a right triangle have to satisfy the Pythagorean Theorem, or a² + b² = c².
a² + b² = c²
14² + 48² = 50²
196 + 2304 = 2500
2500 = 2500
So the first answer, 50, 48, 14, could be the measurements of a right triangle.
Answer:
G=(T²+N²)/4
Step-by-step explanation:
(√4G-N²)²=T²
4G-N²=T²
4G=T²+N²
G=(T²+N²)/4
if anything is unclear, ask freely.
H=9;8)B=(5;4) (ball)R=(7;0) (hit point)B'=symetric of B axis perpendicular of x in RB'=(7+(7-5);4)=(9;4)Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4
no, you will not make your putt.
I hope this helps you and have a great day!! :)
Let's assume that both angles are, in fact, obtuse supplements. We know that supplementary angles must add up to 180°. We also know by definition that obtuse angles are greater than 90°. If we were to take the two supplementary, obtuse angles, ∡A=90+x and ∡B=90+y, with x and y equaling positive real numbers, then we should be able to say that 180=m∡A+mB, or 180=90+x+90+y. By simplifying we get that 180=180+x+y. Simplify further and you get that 0=x+y. If we define x in terms of y, then x= -y. If we define y in terms of x, then y= -x. Because either x or y must be negative to make this statement true, one of the angle measures must be less than 90. If one of the angles must be less than 90 while the other is greater than 90, then one angle MUST be acute if the other is obtuse in order for them to be supplements of each other.
Answer:
5 Miles
Step-by-step explanation:
Given, Height of the tower is 3 miles and the distance from the base is 4 miles.
According the Pythagoras Theorem, the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.
So, putting the data in Pythagoras theorem, let's consider A= 3 and B= 4.
So C will be,
sqrt(A^2 + B^2 )= C
Or, sqrt( 3^2+ 4^2)= C
Or, sqrt( 9+ 16) = C
Or, sqrt(25) = C
Hence, C = 5
So, The distance would be 5 Miles.