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allsm [11]
2 years ago
11

Solve for x. Enter the solutions from least to greatest.

Mathematics
1 answer:
Anna [14]2 years ago
5 0

Answer:

lesser x = -6

greater x = 12

Step-by-step explanation:

(x - 3)^2 - 81 = 0

(x - 3)^2 = 81

x - 3 = +/- 9

x - 3 = 9   or   x - 3 = -9

x = 12   or   x = -6

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ahrayia [7]
Its 8/10 or 12/15 because 4 times 2 is 8 and 5 times 2 is ten
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3 years ago
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What is an number between 300 and 400 it is divisible by 5 and 9
Readme [11.4K]
The answer is 360. 360 divided by 9 is 40, and 360 divided by 5 is 72. hope this helps!
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Julie has two bags of grapes. One weighs 5/8 pound and the ther weighs 1/4 pound. What is the difference in the two bags of grap
ICE Princess25 [194]

Answer:

one bag is heavier and the other is lighter.

Step-by-step explanation:

5/8 = more than half a pound

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2 years ago
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What substitution should be used to rewrite 16(x3 + 1)2 – 22(x3 + 1) – 3 = 0 as a quadratic equation?
Vesna [10]

Answer:

  z = x^3 +1

Step-by-step explanation:

Noting the squared term, it makes sense to substitute for that term:

  z = x^3 +1

gives ...

  16z^2 -22z -3 = 0 . . . . the quadratic you want

_____

<em>Solutions derived from that substitution</em>

Factoring gives ...

  16z^2 -24z +2z -3 = 0

  8z(2z -3) +1(2z -3) = 0

  (8z +1)(2z -3) = 0

  z = -1/8  or  3/2

Then we can find x:

  x^3 +1 = -1/8

  x^3 = -9/8 . . . . . subtract 1

  x = (-1/2)∛9 . . . . . one of the real solutions

__

  x^3 +1 = 3/2

  x^3 = 1/2 = 4/8 . . . . . . subtract 1

  x = (1/2)∛4 . . . . . . the other real solution

The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.

7 0
3 years ago
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the taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km,
Olegator [25]

Answer:

255

Step-by-step explanation:

total cost paid = fixed cost + total variable cost

total variable cost = distance travelled x variable cost per unit

two equations can be derived from the question

a + 10b = 105  equation 1

a + 15b = 155   equation 2

a = fixed cost

b =  variable cost per unit

Subtract equation 1 from 2

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Substitute for b in equation 1

a + 10(10) = 105

a = 105 - 100 = 5

a = 5

cost of travelling a distance of 25km

5 + 10(25) = 255

3 0
2 years ago
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