For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).
Thus, there are 16 possible sums when three six-sided dice are rolled.
Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.
The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.
That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
</span>
The solution to 5x=35 is..
X=7
5x\5=35/5
Answer:
$1.20
Step-by-step explanation:
3.6/3=1.2
you would divide for the unit rate or in other words simplify it.
The smaller side is 4 units going from point (2,2) to point (6,6) while the biger side is 8 units long going from point (6,6) to point (14,14). So 4 is 1/2 of 8 therefore there is a 1:2 ratio because of 4:8
