Answer:
There are 5.43 grams of NaOCl
Explanation:
The given percent by mass of the solute tells us that out of the 150 g of the solution, 3.62% are due solely to the solute.
In other words, <u>the mass of the solute in the solution is</u>:
- 150 g * 3.62/100 = 5.43 g
Thus, in 150 grams of the given bleach solution, there are 5.43 grams of sodium hypochlorite.
<h3>
<u>Answer;</u></h3>
= 930.23 mL
<h3><u>Explanation</u>;</h3>
Using the combined gas law;
P1V1/T1 = P2V2/T2
Where; P1 = 600 kPa, V1 = 800 mL, and T1 = -25 +273 = 258 K, and
V2= ?, P2 = 1000 kPa, and T2 = 227 +273 = 500 K
Thus;
V2 = P1V1T2/T1P2
= (600 ×800 ×500) / (258 × 1000)
= 930.23 mL
