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Masja [62]
3 years ago
8

If two trucks are moving at the same speed, but truck A has a mass of 3,000 kg, and truck B has a mass of 4,500 kg, what stateme

nt is true?
Question 3 options:

Truck B will have a greater stopping distance.


Truck A will have a greater stopping distance.


Truck B has less kinetic energy.


Truck A has greater kinetic energy.
Chemistry
1 answer:
djverab [1.8K]3 years ago
5 0

We want to compare the kinetic energy of two moving objects, we will see that the correct option is the first one:

"Truck B will have a greater stopping distance."

Remember that the kinetic energy of an object of mass M and velocity V is given by:

E = \frac{M}{2}*V^2

Here we know that truck A and truck B have the same velocity, but truck B has a larger mass.

Knowing that the kinetic energy increases linearly with the mass, we can conclude that truck B has the largest kinetic energy.

Because of this, we can also conclude that truck B will have a greater stopping distance, this happens because there is more kinetic energy that must be dissipated.

So the correct option is the first one:

"Truck B will have a greater stopping distance."

If you want to learn more, you can read:

brainly.com/question/12669551

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Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

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Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

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So the molar mass of CaF₂ is:

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Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=\frac{0.0016 grams*1 mole}{78 grams}

moles=2.05*10⁻⁵

<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF_{2}=\frac{1000 mL*1g}{1mL}

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=\frac{1000 grams*1 mole}{78 grams}

moles=12.82

<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>

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<h3>What are diazonium compounds?</h3>

These are organic compounds in which there are ionic interactions between the azo group (-N₂⁺) and an anion X⁻.

The general structure is RN₂⁺X⁻.

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In the attached files you will find the drawings.

You can learn more about diazonium compounds at

brainly.com/question/9061271

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