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3 years ago

Isn’t the answer just D ?

Mathematics

2 answers:

wolverine [178]3 years ago

4 0

Answer:

yes you are right

Slav-nsk [51]3 years ago

3 0

Answer:

its both c and d! since 9^0 is also 1

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Last year the 6th grade had 350 students. This year there are only 224 students. Which proportion could be used to calculate the

KonstantinChe [14]

Answer:

36%

Step-by-step explanation:

50-224=

126 / 350=

.36 x 100=

36%

hope this helps :)

7 0

3 years ago

When you multiply a number by its reciprocal

faust18 [17]

A reciprocal is the number that is in front of a variable. If it is just the plain variable, it's reciprocal is 1. (Ex. 10x has a reciprocal of 10. 7y has a reciprocal of 7. Sorry if I didn't understand your question, are you looking for a vocabulary word?

5 0

3 years ago

The Friendly Sausage Factory (FSF) can produce hot dogs at a rate of 5,500 per day. FSF supplies hot dogs to local restaurants a

Phantasy [73]

Answer:

a. 5218 hot dogs

b. 18 runs per year

c. 1 day per run

Step-by-step explanation:

(a) Let n represent the number of hotdogs in an optimal run. The number of runs needed in a year is ...

r = (260 hotdogs/day)·(365 days/year)/(n hotdogs/run) = 94900/n runs/year

The number of hotdogs in storage decreases from n at the end of a run to 0 just before a run. The decrease is linear, so the average number in storage is n/2.

We can go to the trouble to write the equation for total cost, then differentiate it to find the value of n at the minimum, or we can just jump to the solution. That solution is ...

holding cost = setup cost

(n/2)·0.46 = (94900/n)·66

n^2 = 94900·66·2/0.46 = 27,232,173.9

n ≈ 5218.446

The optimal number of hotdogs in a run is 5218.

___

(b) The number of runs needed per year is (from part (a)) ...

r = 94900/5218 ≈ 18.187

The number of runs per year is 18.

___

(c) The run lenght is 5218 hotdogs, and the run produces them at the rate of 5500 hotdogs/day, so the run length in days is ...

(5218 hotdogs)/(5500 hotdogs/day) = 0.9487 days

The run length is 1 day.

3 0

4 years ago

Consider the infinite geometric series (∞/Σ/n=1) * -4(1/3)^{n-1}.

raketka [301]

The first four terms of the series probably refer to the first four partial sums.

$\displaystyle\sum_{n=1}^1-4\left(\frac13\right)^{n-1}=-4\left(\frac13\right)^{1-1}=-4$
$\displaystyle\sum_{n=1}^2-4\left(\frac13\right)^{n-1}=-\frac{16}3$
$\displaystyle\sum_{n=1}^3-4\left(\frac13\right)^{n-1}=-\frac{52}9$
$\displaystyle\sum_{n=1}^4-4\left(\frac13\right)^{n-1}=-\frac{160}{27}$

which you can compute either by adding one term at a time, or using the well-known formula,

$\displaystyle\sum_{n=1}^kar^{n-1}=a\frac{1-r^{k+1}}{1-r}$

(I can provide a link to a derivation I gave in a nearly identical question in the comments)

The series converges as $k\to\infty$ if and only if $|r|$ , which is certainly the case here, since $-1$ .

Extrapolating from the formula above, the sum of the convergent series is

$\displaystyle\sum_{n=1}^\infty ar^{n-1}=\frac a{1-r}$

so the sum for this series is $\dfrac{-4}{1-\frac13}=-6$ .

5 0

4 years ago

What is the equation, in slope-intercept form, of the line that passes through (0, 6) and has a slope of 4??

frozen [14]

I hope this helps you

5 0

4 years ago

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