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3 years ago

I don't usually get stuck on stuff like this bu For whatever reason I have no idea

Mathematics

2 answers:

Elza [17]3 years ago

6 0

Answer:

the answer is x= -1

Step-by-step explanation:

I know this because 72x-1 is the same as 72 divided by 1 which is 1

Archy [21]3 years ago

4 0

Answer:

1/72=x (part a)

1/70=x (bart b)

Step-by-step explanation:

Divide 1 by 72 for part a, and divide 1 by 70 for part b.

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10) -15xy + 25x ????????????????????

Ierofanga [76]

Factor (−15x)(y)+25x

−15xy+25x

=5x(−3y+5)

Answer:

5x(−3y+5)

6 0

3 years ago

Sherman has 3 cats and 2 dogs. He wants to buy a toy for each of his pet. Sherman has $22 to spend on pet toys. How much can he

svetlana [45]

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3 0

3 years ago

Read 2 more answers

Tyra is laying down square carpet pieces in her photography studio. Each square carpet piece is 1 yard by 1 yard. If Tyra's phot

irakobra [83]

Studio = 7 yards by 4 yards

Area = 7*4 = 28 square yards.

Area of square carpet = 1 yard * 1 yard = 1 square yard

Number needed = Area of studio / Area of square carpet = 28 / 1 = 28

Number needed = 28

3 0

3 years ago

Bella wants to know how tall the oak tree in her back yard is, so she picks

melamori03 [73]

Answer:

B = 62.9ft

Step-by-step explanation:

The distance where she is from the oak tree is 75ft,

The angle of elevation the stone makes with the top of the oak tree is 40°

The height of the tree is x ft

See attached document for better illustration

Using SOHCAHTOA,

Tanθ = opposite/ adjacent

θ = 40°

Opposite = x ft

Adjacent = 75ft

Tan40 = x / 75

X = 75 × tan40

X = 75 × 0.8390

X = 62.92ft

The height of the oak tree is 62.9ft

5 0

3 years ago

The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible meas

tatuchka [14]

Answer: $14\ ft$

Step-by-step explanation:

Given

Length of rectangle is $6\ ft$

Perimeter must be greater than 40 ft

Suppose l and w be the length and width of the rectangle

$\Rightarrow \text{Perimeter P=}2(l+w)\\\Rightarrow P\geq 40\\\Rightarrow 2(l+w)\geq40\\\Rightarrow l+w\geq20\\\Rightarrow w\geq20-6\\\Rightarrow w\geq14\ ft$

So, the smallest width can be $14\ ft$

5 0

3 years ago