Answer:
A
Step-by-step explanation:
Hope this helps!
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2 answers:
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Look at the picture.
c.
1 unit right (+1); 2 units down (-2)
A(1, 3) → A'(1+1, 3-2) → A'(2, 1)
B(4, 5) → B'(4+1, 5-2) → B'(5, 3)
C(3, 1) → C'(3+1, 1-2) → C'(4, -1)
d.
(x, y) → (x + 1, y - 2)
Answer:
V = 2000r³/3
Step-by-step explanation:
We know that the base is a circular disk, so it creates a circle on the xy plane. It would be in the form x² + y² = r². In other words x² + y² = (5r)². Let's isolate y in this equation now:
x² + y² = (5r)²,
x² + y² = 25r²,
y² = 25r² - x²,
y = √25r² - x² ---- (1)
Now remember that parallel cross sections perpendicular to the base are squares. Therefore Area = length^2. The length will then be = 2√25r² - x² --- (2). Now we can evaluate the integral from -5r to 5r, of [ 2√25r² - x² ]² dx.
As you can see, your exact solution would be, V = 2000r³/3. Hope that helps!