You need to factor the radicals into products of radicals, and when factoring you should keep in mind you want to obtain perfect square roots. So √125 = √5*√25 and squareroot 25 has a definite answer of 5, so ∛125=∛5×∛25=5×√5. You want to follow the general pattern of factoring perfect squares to obtain a number outside the radical which can be multiplied by the current coefficient
Answer:
the computer cost $712.50 and the printer cost $237.50
Step-by-step explanation:
cause $950 divided by 4 is $237.50 you can check the answer by doing 237.50 times 4
I’m confused at what you are asking
Answer:
1/2
Step-by-step explanation:
The Rational Root Theorem says that any rational root has
1. a numerator that is a factor of the constant term
2. a denominator that is a factor of the leading coefficient (that's attached to the highest-power term)
Numerator: 
Denominator: 
That means there are only two possible rational roots: 
Try them both by plugging them into the polynomial.
Aha! The negative one-half value does not produce 0
Answer:
Step-by-step explanation:
Given that,
f(x, y) = xe^−x(1 + y) x ≥ 0 and y ≥ 0
It is f(x, y)= 0 otherwise
To find probability of life time, we will take the double integral of the function with respect to X and Y
Y ranges from 0 to ∞
X exceed 5, so it ranges from 5 to ∞
∫ ∫ f(x, y) dxdy
∫ ∫ xe^−x(1 + y) dxdy
∫ ∫ x•e^(−x -xy) dxdy
Separating the exponential
∫ ∫ x•e^(−x) • e^(-xy) dxdy
Integrating with respect to y and keeping x as a constant.
∫ x•e^(−x) • e^(-xy) / -x dx
∫ - e^(−x) • e^(-xy) dx y = 0 to y=∞
∫ - e^(−x) • [e^(-∞) - e^(0) ]dx
∫ - e^(−x) • [ 0 - 1] dx
∫ - e^(−x) • -1 dx
∫ e^(−x) dx
Now integrating this
e^(-x) /-1 from x=5 to x=∞
-e^(-x) from x=5 to x=∞
- [ e^(-∞) - e^(-5)]
- (0-e^(-5))
- - e^(-5)
e^(-5) = 0.006738
To 3d.p =0.007
Then probability that the life time X exceed 5 is 0.007
