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3 years ago

Find the exact length of the third side. 73 55

Mathematics

1 answer:

DerKrebs [107]3 years ago

6 0

Answer:

91.4

Step-by-step explanation:

We know that the formula to a right triangle is a^2 + b^2 = c^2

so assume 73 and 55 are both Not the hypotenuse, then

73*73 + 55*55 = c^2

5329 + 3025 = 8354

c = 91.4

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Rachel, Kayla, and Francesca raised $35.67 for their basketball team. Rachel and Kayla each raised the same amount, and Francesc

nata0808 [166]

Answer: Expression for the amount raised by Rachel = x

Expression for the amount raised by Francesca = x+10.50

Step-by-step explanation:

Let x = the amount raised by Kayla.

Since Rachel and Kayla each raised the same amount.

then, expression for the amount raised by Rachel = x

Francesca raised $10.50 more than each of them.

Then, expression for the amount raised by Francesca = x+10.50

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3 years ago

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Step-by-step explanation:

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3 years ago

Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and

earnstyle [38]

Answer:

2x²-2x-24

Step-by-step explanation:

Something has roots of 4 and -3 we can write

(x-4)(x+3)

We then attach a constant, a that will ensure that it passes through the correct point

a(x-4)(x+3)

now plug in the numbers and solve for a

a(3-4)(3+3)= -12

a(-1)(6)= -12

-6a= -12

a=2

So we have

2(x-4)(x+3)

and now it's just a matter of mulitplying/simplifying things

(x-4)(x+3)= x²-x-12

2(x²-x-12)= 2x²-2x-24

6 0

3 years ago

Read 2 more answers

What is the perimeter of the figure?

Ad libitum [116K]

Answer: 22^yd

Step-by-step explanation:

7 0

3 years ago

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (

alisha [4.7K]

Answer:

Point estimation of the mean = 17.6

Error = 4.6

95% CI: 13.0 ≤ μ ≤ 22.2

The distribution can be approximated to a normal because the sample size n=50 is bigger than 30.

Step-by-step explanation:

We have this information:

- Sample mean:

$\bar{X}=17.598$

- Sample standard deviation

$s=16.01712719$

- Sample size

$n=50$

For now on, we round to one decimal place.

The best estimation for the population mean is the sample mean

$\mu=\bar{X}=17.6$

The margin of error is equal to the t-value multiplied by the sample standard deviation and divided by the sample size.

The t value depends on the degrees of freedom and the width of the confidence interval. In this case it is a 95% CI and the degrees of freedom are 49. For this conditions, the t-value is t=2.01.

Then, the margin of error is

$E=t_{49}*\sigma/\sqrt{n}=2.01*16.0/\sqrt{50}=4.553$

Then, the confidence interval can be constructed as:

$\bar{X}-t\sigma/\sqrt{n}\leq\mu\leq\bar{X}-t\sigma/\sqrt{n}\\\\17.6-4.6\leq \mu \leq 17.6+4.6\\\\ 13.0\leq \mu \leq 22.2$

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3 years ago