Answer:
a) 28 cases
b) 3 cases
Explanation:
a) From the table of genetic codes, there are 28 codons that specify more than one amino acid assuming only the first two nucleotides are considered. In these cases, one cannot outrightly specify the amino acid the genetic codes are coding for without knowing the last nucleotide of the codes. <em>For example, UU can be for Phenylalanine or Leucine, CA can be for Histidine or Glutamine, etc. </em>
b) From the table of genetic codes, the first two nucleotides of Arginine can be either of CG or AG, that of Serine can be either of UC or AG while that Leucine can be either of CU or UU. Only in these <u>3 cases</u> would one fail to know which are the first two nucleotides assuming the name of the amino acids are given.
<em>See the attached image for the genetic code.</em>
One way is to see if it responds to stimulants or if it reproduces
You would find layers in a sedimentary rock, because it has different types of other rock combined in it.
Answer:
1/3
Explanation:
<em>A standard monohybrid cross is a cross that follows the dominance/recessive pattern from Mendel's experiment.</em>
It means the purple flower color is dominant over the white flower color.
Assuming the allele for purple flower color is P and that of the white flower color is p, a standard monohybrid cross will involve a true breeding PP and pp.
PP x pp: Pp, Pp, Pp and Pp. All the F1 offspring will have purple flowers with Pp genotype.
At F2: Pp x Pp = PP, Pp, Pp, and pp.
3/4 or 75% of the F2 offspring have purple flower color out of which 1 is true breeding for the trait.
Hence the fraction of the purple flowered peas in the F2 that is expected to be true-breeding (PP) is 1 out of 3.
