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Tatiana [17]
3 years ago
5

Suppose that individuals 7 and 8 are pregnant with another daughter. Can you tell in advance whether she will be a carrier or wi

ll have the disease?
Biology
2 answers:
VashaNatasha [74]3 years ago
5 0

Its B : Yes, she will be a carrier of hemophilia.

Harman [31]3 years ago
4 0
It all just depends on what genes they carry. You can create a Punnet Square to determine the percentage of obtaining a specific disease.
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A rare genetic disease which is due to a recessive allele (a) and that is lethal when homozygous, occurs within a specific popul
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Answer:

40 individuals

Explanation:

The homozygous recessive percentage is equal to q2.

Recessive genotype frequency, q 2 is 1/1000000  = 0.000001  

therefore, q = \sqrt{q2}  = \sqrt{0.000001 }  = 0.001 =  allele "a" frequency  

and p + q = 1, thus, p = 1 – q = 1 – 0.001 = 0.999  

thus, the frequency of allele a = q = 0.001  and the frequency of allele A = p = 0.999

Carriers are heterozygous and are equal to 2pq.  

So, 2pq = 2  x 0.999 x 0.001 x  20,000 = 39.96 (round of to 40)

Hence, 40 individuals will be expected to carry the recessive allele.

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3 years ago
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Answer:

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St St st st. hope this is helpfull
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