Answer:
B. BC=12, FH=9
Step-by-step explanation:
I guessed and it was right
Answer:
Step-by-step explanation:
Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.
If |PQ|=2k, then
a2(cosp−cosq)2+b2(sinp−sinq)2=4k2
The coordinates of M are
xy==a2(cosp+cosq)b2(sinp+sinq)
Answer:
D
Step-by-step explanation:
f(x) - g(x) = -9x^2 - 7x + 12 - (3x^2 - 4x - 15) Remove the brackets
f(x) - g(x) = -9x^2 - 7x + 12 - 3x^2 + 4x + 15
f(x) - g(x) = -9x^2 - 3x^2 - 7x + 4x + 12 + 15
f(x) - g(x) = -12x^2- 3x + 27
Answer D
<em>You would use AAS because of the fact that there is two angles and the angle where both triangles instersect and create a verticle angle, there is no angle written. It has an angle then another angle then a side. Hope this helps!</em>
Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
