Since the distance of MN is 31 and we have a distance of ML
of h -15 and LN of 2h – 8, therefore
ML + LN = h -15 + 2h – 8 = 31
h = 18
substituting the value of h to the expression for LN
obtaining
LN = 2h – 8
LN = 2(18) – 8
LN = 28
Therefore the length of the segment LN is 28 units
Answer:
10a+3b÷c/3
Step-by-step explanation:
let the first number be a
second be b
third be c
10×a +3×b ÷c÷3
10a+3b÷c/3
=10a+3b÷c/3
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